All categories

3 years ago

What is the scale factor of figure ABCD?

Mathematics

1 answer:

ivann1987 [24]3 years ago

6 0

We know that
measure ABCD=scale factor*[measure A1B1C1D1]

in the axis of the y coordinate
we have
scale factor=measure ABCD/measure A1B1C1D1
scale factor=3/1----->3

in the axis of the x coordinate
we have
scale factor=measure ABCD/measure A1B1C1D1
scale factor=8/6----->4/3

therefore

the answer is the option
d. the figure isn't dilated properly

You might be interested in

PLZZZZZZZZZZZZZZZZZZZZZ ANSWER IF ANSWERED YOU GET 98 POINTS HURRY!!!!!!!!!!!!!!!!!!

LekaFEV [45]

Answer:

y = 3x + C

y = mx + 5

y = 3x + 5

Step-by-step explanation:

A. The standard form for lines with slope = 3 is

y = 3x + C where C is the y-intercept and can be any number

B. The standard form for lines with y-intercept = 5

y = mx + 5 where m is the slope and can be any number

C. The only line with slope = 3 and y-intercept =5

y = 3x + 5

There is only one line because both m and C are given.

5 0

3 years ago

Read 2 more answers

A radioactive substance decays at a continuous rate of 17% per year, and 250 mg of the substance is present in the year 2009.

yaroslaw [1]

Answer:

a) $A(t) = 250 (1-0.17)^t = 250(0.83)^t$

b) $A(t=14) = 250 (0.83)^{14}= 18.408 mg$

c) For this case we want to find when the quantity is below 25 mg, so we can do this:

$25 = 250 (0.83)^t$

We can divide both sided by 250 and we got:

$0.1 = 0.83^t$

Now we can apply natural log on both sides and we got:

$ln(0.1) = t ln (0.83)$

And if we solve for t we got:

$t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years$

So the answer for this case would be 12.358 years after.

Step-by-step explanation:

Part a

For this case we know that the decay rate per year is about 17% or 0.17 in fraction and the initial amount is 250 mg for 2009, we can define the model like this:

$A(t) = A_o (1-r)^t$

Where A represent the amount of the substance in mg, r the decay rate = 0.17 and t the number of years after 2009.

Our model for this case would be:

$A(t) = 250 (1-0.17)^t = 250(0.83)^t$

Part b

For this case we have that t= 2023-2009=14 years, so then we can find the amount of substance like this:

$A(t=14) = 250 (0.83)^{14}= 18.408 mg$

Part c

For this case we want to find when the quantity is below 25 mg, so we can do this:

$25 = 250 (0.83)^t$

We can divide both sided by 250 and we got:

$0.1 = 0.83^t$

Now we can apply natural log on both sides and we got:

$ln(0.1) = t ln (0.83)$

And if we solve for t we got:

$t = \frac{ln(0.1)}{ln(0.83)}= 12.358 years$

So the answer for this case would be 12.358 years after.

6 0

3 years ago

Plz help me this is for tomorrow waited last minute

soldi70 [24.7K]

Angle a =40° beacuse they are vertical angle
b will be 180- 40+90=50°
c is making supplementry angle with 65 so c+65=180
c=115°

8 0

4 years ago

The lifetimes of 10,000 watch batteries are normally distributed the mean lifetime is 500 days the standard deviation is 60 days

Lelu [443]

Given:
μ = 500 days, the population mean
σ = 60 days, the population standard deviation

Therefore
μ + σ = 560
μ - σ = 440
μ + 2σ = 620
μ - 2σ = 380
μ + 3σ = 680
μ - 3σ = 320

The figure shown below illustrates the normal distribution
About 68% of the total area lies in x = (μ-σ, μ+σ)
About 95% of the total area lies in x = (μ-2σ, μ+2σ)
About 99.7% of the total area lies in x = (μ-3σ, μ+3σ).

7 0

4 years ago

What is the discriminant of 3x2 + 6x = 2? 12 18 42 60

zimovet [89]

The correct answer is option D i.e. 60 The given equation is : 3x^2 + 6x - 2 = 0 The discriminant is given as = {b^2 - 4ac}/2a; where a = 3, b = 6 and c = -2d Thus, D = {6^2 - 4(3)(-2)} or D = {36 + 24} or D = 60

5 0

4 years ago

Read 2 more answers