How would you solve this equation? It uses logarithms.

Mathematics

1 answer:

slega [8]3 years ago

4 0

$\bf log_{{ a}}\left( x^{{ b}} \right)\implies {{ b}}\cdot log_{{ a}}(x)\\\\
-----------------------------\\\\
2^{x+1}=5^{2x-1}\implies log(2^{x+1})=log(5^{2x-1})
\\\\\\
(x+1)log(2)=(2x-1)log(5)\implies (x+1)\cfrac{log(2)}{log(5)}=(2x-1)
\\\\\\
now\quad \cfrac{log(2)}{log(5)}\textit{ is just a constant about }0.43068$

and you can simply solve that for "x"

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Answer:

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kicyunya [14]

Answer:

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Step-by-step explanation:

Let

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we know that

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Solve the quadratic equation using a graphing calculator

The solution is x=44

see the attached figure

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therefore

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3 years ago

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Alisiya [41]

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