I think Theodosius the best measure. The outliers will not effect the measure. If you use mean, you add all the data points and divide by the number of data points. The extremes will skew the data. If you use mode, that may work also. You find the data that occurs most often.
Answer:
The answer is "
"
Step-by-step explanation:
In this question, the image file is missing, which is defined in the attached file. please find it.
I am pretty sure number 3 is the right answer
Answer:
Inequaliy: 2x-3(12)>60
X>48
Step-by-step explanation:
Since area of a rectangle is W(L)=A
The inequality given right here including length And width and area Plugged in would be
2x-3(12)>60. (It’s >60 because the area stated in the problem said to be greater then 60 so we put a Greater then sign)
Combine like terms and solve
2x-36>60
Add 36 on both sides
2x>96
Divide 2 on both sides to isolate variable
x>48
Check:
2(50)-36>60 ( I used 50 because it’s greater then 48 and it’s a easy number to work with for just a check)
solve:
100-36>60
64>60✔️
You would just do 13+15+26+32 which would equal 86mm
