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Andru [333]
3 years ago
14

Identify 21, 46, and 57 as prime or composite. HELP!!

Mathematics
1 answer:
vlada-n [284]3 years ago
4 0

Answer:

Composite, Composite, composite

Step-by-step explanation:

all of them can be divided

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Jerome works as a waiter. He earns $80 each weekend plus 15% in tips based on the cost of the meals served.
Softa [21]

Answer:

He gets paid $80 each weekend, and a 15% with tips.

you would need to figure out the tips, by taking the $725 and timesing it by .15 for the percent.

which would be 108.75

you would now take 108.75 and add 80 to get what he made that weekend.

108.75+80 = 188.75 dollars

Step-by-step explanation:

5 0
3 years ago
How would you do this question?
diamong [38]

Answer:

1) ∫ x² e^(x) dx

4) ∫ x cos(x) dx

Step-by-step explanation:

To solve this problem, eliminate the choices that can be solved by substitution.

In the second problem, we can say u = x², and du = 2x dx.

∫ x cos(x²) dx = ∫ ½ cos(u) du

In the third problem, we can say u = x², and du = 2x dx.

∫ x e^(x²) dx = ∫ ½ e^(u) du

8 0
3 years ago
Suppose in the University of Manitoba, 40% of the students live in apartments. If 600 students are randomly selected, then the a
just olya [345]

Answer:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

Step-by-step explanation:

The exact way to solve this problem is using the binomial distribution, assuming that our random variable of interest is "number of students living in apartments" represented by X and X \sim Bin(n=600, p =0.4)

And we want this probability:

P(200 \leq X \leq 400) [tex]In order to find this probability we can use the foloowing excel code:"=BINOM.DIST(400,600,0.4,TRUE)-BINOM.DIST(199,600,0.4,TRUE)"And we got:[tex] P(200 \leq X \leq 400) =0.999675[tex]But for this case the problem says that we need to approximate, so then we can use the normal approximation to the normal distribution. We need to check the conditions in order to use the normal approximation.
[tex]np=600*0.4=240\geq 10

n(1-p)=600*(1-0.4)=360 \geq 10

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

E(X)=np=600*0.4=240

\sigma=\sqrt{np(1-p)}=\sqrt{600*0.4(1-0.4)}=12

And then X \sim N (\mu = 240, \sigma= 12)

And we are interested on the following probability:

P(200\leq X\leq 400)=P(\frac{200-240}{12}\leq \frac{X-\mu}{\sigma}\leq \frac{400-240}{12})=P(-3.33\leq Z \leq 13.33)

=P(Z

So then the correct answer would be:

B) .9996

6 0
3 years ago
Can someone help me solve this
Rainbow [258]

Answer:

x=21

Step-by-step explanation:

since the triangle is isosceles, the two lower angles are equal.

2(2x+3)=90

4x+6=90

4x=84

x=21

4 0
2 years ago
Does anyone know the answer to 2/3 divided by 1/6
saveliy_v [14]

Answer:

4

Step-by-step explanation:

You would first do 2/3 times 6/1 which is 12/3. Then you would simplify and divide 12 by 3 to get 4.

7 0
3 years ago
Read 2 more answers
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