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inn [45]
3 years ago
10

9 UT

Mathematics
1 answer:
sveticcg [70]3 years ago
3 0

Answer:

Bdbebdbeb

Step-by-step explanation:

Bbbsbdb

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\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }

Step-by-step explanation:

hello,

we can write

fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}

hope this helps

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