Answer:
The standard error of the mean is 0.0783.
Step-by-step explanation:
The Central Limit Theorem helps us find the standard error of the mean:
The Central Limit Theorem estabilishes that, for a random variable X, with mean 
and standard deviation 
, a large sample size can be approximated to a normal distribution with mean and standard deviation 
.
The standard deviation of the sample is the same as the standard error of the mean. So
In this problem, we have that:
So
The standard error of the mean is 0.0783.
5.46 to 3 sig figs means the range is {5.455,5.465} and 17.74 means the range {17.735,17.745}.
p=q²/r has a maximum value when q=5.465 and r=17.735 and a minimum value when 5.455 and r=17.745.
So the range of p is 1.6769 to 1.6840. When we have 2 decimal places we get p=1.68 which accommodates the maximum and minimum values of the range. So 2 decimal places is a suitable degree of accuracy, or we could say 3 significant figures.
Answer:
The rate is 0.9 gallon per minute
Step-by-step explanation:
Here, we have 4.5 gallons drained in 5 minutes but we are interested in calculating the rate per minute
Let the amount drained per minute be x
4.5 gallons = 5 minutes
x gallon = 1 minute
Let’s cross multiply;
x * 5 = 4.5 * 1
5x = 4.5
x = 4.5/5
x = 0.9 gallons
The measurement for The measurement for arc AC is 99.8
