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2 years ago

Find the gradient of each of these line y = 2x + 4

2 answers:

8 0

We Know, Principle equation of a line is: y = mx + c
Here, we have: y = 2x + 4

Compare the equations,
Gradient of line (m) would be equal to 2

In short, Your Answer would be 2

Hope this helps!

Kitty [74]2 years ago

3 0

Y = 2x + 4

comparing to y = mx + c, where m = slope or gradient of the line and c = vertical intercept.

y = 2x + 4 and y = mx + c

m = 2

Hence the slope or gradient of the line = 2

Hope this explains it.

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3 years ago

Plz help!!<br> Consider the given right triangle.

aalyn [17]

Answer:

b = 8

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Step-by-step explanation:

From the given right triangle,

a = $8\sqrt{3}$ , m(∠B) = 30°

By applying sine rule in the given triangle,

cos(B) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

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2 years ago

Segment CD has point E located on it such that CE:ED = 3:5. If the endpoints are located at C(5, -6) and D(11,18) then what are

wlad13 [49]

Answer:

E(29/4,3)

Step-by-step explanation:

Given that,

Segment CD has point E located on it such that CE:ED = 3:5

The coordinates of C and D are (5, -6) and (11,18) respectively.

We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :

$(x,y)=(\dfrac{m_1x_2+m_2x_1}{m_1+m_2},\dfrac{m_1y_2+m_2y_1}{m_1+m_2})\\\\(x,y)=(\dfrac{3(11)+5(5)}{3+5},\dfrac{3(18)+5(-6)}{3+5})\\\\=\dfrac{29}{4},3$

So, the coordinates of E are (29/4,3).

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3 years ago

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zysi [14]

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3 years ago