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Romashka [77]
3 years ago
6

Which of the following numbers is irrational?

Mathematics
2 answers:
Ad libitum [116K]3 years ago
5 0
The square root of 3 is irrational since it is not a perfect square.

Alex17521 [72]3 years ago
4 0
2/3 is irrational, since as a decimal, it never ends. The number would be .66666 repeating.
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A Turtle Crawled 0.06617 kilometers. How many millimeters is this?​
Paul [167]

Answer:

66170 mm

Step-by-step explanation:

0.06617 km * 1000 km/m * 1000 m/mm = 66170 mm

4 0
3 years ago
Which type of triangle has side measures of 6 cm, 7 cm, and 12 cm and one angle with a measure of 135°?
Fittoniya [83]

Answer:

Hm I dont know if im right but im thinking it's a scalene, because the sides are not equal, or a obtuse triangle, because one side is more than 90 degrees. Hope this helps!

5 0
3 years ago
Select the correct equation that represents an am signal.
ch4aika [34]

The first choice,

... a. s(t) = ac[1 + μam cos (2πfmt)] cos (2πfct)

has the carrier frequency cos(2πfct) amplitude modulated by the message signal.

The other expressions represent frequency and phase modulation of various kinds.

8 0
3 years ago
V= 512^2/3* 19683^1/3*256^1/4
irina1246 [14]

Answer:

V=512^2/3* 19683^1/3*256^1/4    = 6912

Step-by-step explanation:

V= (512^{\frac{2}{3} } ) \times (19683^{\frac{1}{3} } )\times  (256^{\frac{1}{4} } )\\

As

2^{9}  = 512\\2^{8} =  256\\19683^{\frac{1}{3} } = 27\\

putting values in equation

V= 2^{9(^{\frac{2}{3} } )} \times 27 \times 2^{8^({\frac{1}{4}) } } \\  let it be equation 1

As

2^9^{\frac{2}{3} }  = 2^6    according\,to\,exponential\,rule\\2^8^\frac{1}{4} =     2^2     according\,to\,exponential\,rule\\\\

putting values in equation 1

V= 2^6\times 27\times 2^2

According to exponential rule 2^6 \times 2^2 = 2^8

V=2^8 \times 27\\

V=256\times 27\\V=6912

So

V= 6912

Keywords: Algebra

Learn more about algebra at:

  • brainly.com/question/3739260
  • brainly.com/question/13168205
  • brainly.com/question/9607945

#learnwithBrainly

7 0
3 years ago
For what values of (m) does the graph of y=mx²-5x-2 have no x-intercepts?
Natali5045456 [20]
You need to find where the discriminant is less than zero
Remember the discriminant is b^2 - 4ac
a = m
b = -5
c = -2
Set up the inequality like this
(-5)^2 - 4m(-2) < 0
25 + 8m < 0
8m < -25
m < -25/8 < -3.125

So any number less than -3.125 will make this graph have no x-intercepts (or real roots)
5 0
3 years ago
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