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Arte-miy333 [17]
3 years ago
5

Find the height of the tree

Mathematics
2 answers:
strojnjashka [21]3 years ago
6 0
Where is the imange of the tree
SpyIntel [72]3 years ago
5 0
Sorry you’ll need to upload an image of the problem. We do not know any information of the tree
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The gradient of the line y= -2x -3​
N76 [4]

Answer:

-2

Step-by-step explanation:

The equation of the line is written in y=mx+c form, where m is the gradient and c is the y-intercept.

In this case, your m is a -2 and your c is a -3.

Hence the gradient of the line is -2.

5 0
3 years ago
One of your responsibilities as a line cook is to
vfiekz [6]

Answer: 72

Step-by-step explanation:

If all the sandwiches will have a slice of cheese, you just need to add up all of the sandwiches order (28 + 14 + 30 = 72)

5 0
3 years ago
The cost of four cell phones are $345,$400,$110,and$640 What is the Median cost
garri49 [273]

Answer:

372.5

Step-by-step explanation:

Order the numbers least to greatest:

110, 345, 400, 640

Add the two middle numbers:

345+400= 745

Divide 745 by 2:

372.5

6 0
3 years ago
Tony is driving from alma ,Michigan to Elizabeth city, North Carolina . The drive covers a total distance of 1,100 miles. Tony c
Natalka [10]
<span>3 tanks because he can do 400 miles on tank, and he's goin 1,100 miles, he does 400 miles with first tank, next tank he gets to 800 miles, and then he uses 3/4 of last tank to get to 1,100, he will then have 100 miles left on the tank though.</span>
4 0
3 years ago
Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and
pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0
3 years ago
Read 2 more answers
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