Refer to matrix B and identify the matrix element 614.

Match the terms to their correct definitions.

Inessa [10]

Not 100% positive, but I think that it’s
13
10
9
16
15
11
14
12
I hope this helps

5 0

2 years ago

Simplify each radical

const2013 [10]

Answer:

AECG

Step-by-step explanation:

1

sqrt(49) = 7

sqrt(a^2) = a

sqrt(b^2) = b

For every two variables you can take one out from under the root sign and thorough the other one away.

Answer: E

2

sqrt(36) = 6

sqrt(a^2) = a See comment for 1.

b must be left where it is. There is only 1 of them.

6asqrt(b)

Answer: A

3. sqrt(25) = 5

sqrt(b^2) = b

a must be left alone. There's only 1 of them.

5b sqrt(a)

answer: C

4

sqrt(81 a b)

sqrt(81) = 9

The variables must be left alone. There's only1 of them

9 sqrt(ab)

Answer G

8 0

2 years ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

2 years ago

The initial number of views for a certain website was 15. The number of views is growing exponentially at a rate of 22% per week

Oksi-84 [34.3K]

t he number of views expected to be four weeks from now can be calculated using the equation:

F = P ( 1+i)^n

Where F is the future views

P is the present views

i is the percent increase in views

n is the number of weeks

F = 15 ( 1+ 0.22)^4

F = 33 views