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Jet001 [13]
3 years ago
14

Help help help pleaseeee

Mathematics
1 answer:
vovikov84 [41]3 years ago
5 0
First of all, you need to understand that _/x = x^(1/2

3_/6^(6 should be written as 6^(6/3 in the next step, in the first step the square root should be gone already,thus she had made a mistake in step A.

here's a formula to help you understand
\sqrt{2} =  {2}^{ \frac{1}{2} }   \\  \\  \sqrt[3]{ {6}^{6} }   \\   = {6}^{ \frac{6}{3} }  \\  =  {6}^{ \frac{1}{2} }   \\  =  \sqrt{6}

hope it helps!
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The linear equation y = 1/4x tells us that this line is going to be more vertical or horizontal?
Afina-wow [57]
Horizontal, it’s below a 1/2 slope.
5 0
3 years ago
Use the function notation to write a recursive formula to represent the sequence: 4, 8, 12, ...
melamori03 [73]

Answer:

The correct answer is f(n) = f(n − 1) + 4

Step-by-step explanation:

Let us consider the sequence: 4, 8, 12, …

Using f(n) = f(n − 1) + 4, we can easily get the sequence.

As the first term is 4 and next term is obtained by adding 4 to the first term.

i.e. 4+4 = 8

     8+4 = 12

     12+4 = 16  and so on.

Since the next term is obtained by adding 4 to the previous term.

<em>So, f(n) = f(n-1) + 4 would be the correct recursive formula for the function of the sequence 4, 8, 12, .... </em>

<em>Verification: </em>

<em>                 f(n) = f(n-1) + 4</em>

Putting n=2 in f(n) = f(n-1) + 4 to get the second term of the sequence.

<em>                f(2) = f(2-1) + 4</em>

<em>                f(2) = f(1) + 4</em>

<em>                f(2) = 4 + 4</em>

<em>                f(2) = 8</em>

Putting n=3 in f(n) = f(n-1) + 4 to get the third term of the sequence.

<em>                 f(3) = f(3-1) + 4</em>

<em>                 f(3) = f(2) + 4</em>

<em>So, adding 4 in f(2)=8 would give us the next term i.e. 12</em>

<em>                f(3) = 8 + 4</em>

<em>                 f(3) = 12</em>

<em />

Keywords: recursive formula, sequence

Learn more about using recursive formula from brainly.com/question/1851471

#learnwithBrainly<em> </em>

7 0
3 years ago
Coefficient of b in expansion of (3+b)^4
Margarita [4]
Are you sure you want ONLY the coefficient of b?  If you expand this, you will have b in 3 of 4 terms.

According to Pascal's Triangle, the coefficients of (a+b)^4 are as follows:

                             1
                        1    2    1
                   1      3    3     1
              1       4     6     4     1

So (a+b)^4 would be 1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + b^4

Here, you want (3 + b)^4.  Here's what that looks like:

3^4 + 4[3^3*b] + 6[3^2*b^2] + 4[3*b^3] + 1[b^4]

Which coeff did you want?
4 0
3 years ago
What is 9147392 the Rounded nearest thousand
Yuliya22 [10]

Answer: 9,147,000

Step-by-step explanation:

6 0
3 years ago
Yooo help plz :) <br> ASAP <br> ASAP <br> ASAP
german
The 3rd one
You can factor 3 out of each term in the numerator. And then divide it by the 3 in the denominator.
3 0
3 years ago
Read 2 more answers
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