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slavikrds [6]
3 years ago
13

19.43 as a mixed number.

Mathematics
1 answer:
WARRIOR [948]3 years ago
8 0
<span>19 and 43/100................</span>
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Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?
Archy [21]

Answer:

Its false

Step-by-step explanation:

4.42 the .42 the 2 is under 5 so it would round up.

7 0
3 years ago
Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En
ArbitrLikvidat [17]

Answer:

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t, c) x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right), y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right).

Step-by-step explanation:

The equation of the circle is:

x^{2} + (y-1)^{2} = 16

After some algebraic and trigonometric handling:

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1

\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t

Where:

\frac{x}{4} = \cos t

\frac{y-1}{4} = \sin t

Finally,

x = 4\cdot \cos t

y = 1 + 4\cdot \sin t

a) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

b) x = 4\cdot \cos t, y = 1 + 4\cdot \sin t.

c) x = 4\cdot \cos t'', y = 1 + 4\cdot \sin t''

Where:

4\cdot \cos t' = 0

1 + 4\cdot \sin t' = 5

The solution is t' = \frac{\pi}{2}

The parametric equations are:

x = 4\cdot \cos \left(t+\frac{\pi}{2}  \right)

y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)

7 0
3 years ago
Find the measure of the Angle? (Hint not the value of x)<br> 5x +2<br> 4x +17
Anna [14]

Answer:

240 {}^{}

......

7 0
3 years ago
PLZ HELP ME HELP!!!<br>If you explain your process the best, I WILL GIVE you brainliest
ivanzaharov [21]
The answer is 322 m/s. hope this helps :)
1 mi/ 5s x 1609 m/ 1 mi =322 m/s
5 0
3 years ago
What is the horizontal asympote of this graph?
Anna35 [415]

Using it's concept, it is found that the graph has no horizontal asymptote.

<h3>What are the horizontal asymptotes of a function f(x)?</h3>

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, we have that:

  • The function is undefined for x < 0, hence \lim_{x \rightarrow -\infty} f(x) is undefined.
  • For x > 0, the funciton goes to infinity, hence \lim_{x \rightarrow \infty} f(x) = \infty.

Thus, the graph has no horizontal asymptote.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

4 0
2 years ago
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