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3 years ago

19.43 as a mixed number.

Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

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Raj weighs a book and rounds the weights to the nearest tenth. Does this weight round to 1.5 pounds?

Archy [21]

Answer:

Its false

Step-by-step explanation:

4.42 the .42 the 2 is under 5 so it would round up.

7 0

3 years ago

Find parametric equations for the path of a particle that moves along the circle x2 + (y − 1)2 = 16 in the manner described. (En

ArbitrLikvidat [17]

Answer:

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ , c) $x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$ , $y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$ .

Step-by-step explanation:

The equation of the circle is:

$x^{2} + (y-1)^{2} = 16$

After some algebraic and trigonometric handling:

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = 1$

$\frac{x^{2}}{16} + \frac{(y-1)^{2}}{16} = \cos^{2} t + \sin^{2} t$

Where:

$\frac{x}{4} = \cos t$

$\frac{y-1}{4} = \sin t$

Finally,

$x = 4\cdot \cos t$

$y = 1 + 4\cdot \sin t$

a) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

b) $x = 4\cdot \cos t$ , $y = 1 + 4\cdot \sin t$ .

c) $x = 4\cdot \cos t''$ , $y = 1 + 4\cdot \sin t''$

Where:

$4\cdot \cos t' = 0$

$1 + 4\cdot \sin t' = 5$

The solution is $t' = \frac{\pi}{2}$

The parametric equations are:

$x = 4\cdot \cos \left(t+\frac{\pi}{2} \right)$

$y = 1 + 4\cdot \sin \left(t + \frac{\pi}{2} \right)$

7 0

3 years ago

Find the measure of the Angle? (Hint not the value of x)<br> 5x +2<br> 4x +17

Anna [14]

Answer:

$240 {}^{}$

......

7 0

3 years ago

PLZ HELP ME HELP!!!<br>If you explain your process the best, I WILL GIVE you brainliest

ivanzaharov [21]

The answer is 322 m/s. hope this helps :)
1 mi/ 5s x 1609 m/ 1 mi =322 m/s

5 0

3 years ago

What is the horizontal asympote of this graph?

Anna35 [415]

Using it's concept, it is found that the graph has no horizontal asymptote.

<h3>What are the horizontal asymptotes of a function f(x)?</h3>

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, we have that:

The function is undefined for x < 0, hence $\lim_{x \rightarrow -\infty} f(x)$ is undefined.

For x > 0, the funciton goes to infinity, hence $\lim_{x \rightarrow \infty} f(x) = \infty$ .

Thus, the graph has no horizontal asymptote.

More can be learned about horizontal asymptotes at brainly.com/question/16948935

#SPJ1

4 0

2 years ago