There is more than 1 way to do this but the way i use is to go back to zero and move that amount of spaces to left if the original integer is positive or to the right if the original integer is a negative
Answer: (g+5)-8
Step-by-step explanation:
Hello from MrBillDoesMath!
Answer:
x = 3
Discussion:
(
23 + 3x) + (8x-41) = 15 =>
23 - 41 + 3x + 8x = 15 =>
-18 + 11x = 15 =>
11x = 15 + 18 = 33 =>
x = 33/11 = 3
Thank you,
MrB
Not so sure maybe is not but just try with 5.