Ask question

Ask question

All categories

Montano1993 [528]

3 years ago

8

as a medical technician, Stephanie has been offered a job that pays $53 000.00 per year and another job that pays $25.50 per hou

r. assuming a 40 hour work week and all other conditions being the same, at which job will she earn more?

1 answer:

ohaa [14]3 years ago

7 0

Answer:

25.50x40= 1020/ week

times 52 weeks- $53040

You might be interested in

Pie

Answer:

I

1)-574 2)-874 3)-902 4)No answer bz have two dismal place

8 0

2 years ago

2. Tristan wants to go bowling. He wants to spend no more than $25. It costs $3.00 to rent shoes and $4.50 for each game. What i

liubo4ka [24]

Answer:

$3 + 4.50g \leq 25$

$g\leq 4$

Step-by-step explanation:

25 - 3 is 22. 22 divided by 4.50 is a decimal. But it rounds down to 4. So the most amount of games Tristan can play is 4.

Hope it helps!

6 0

2 years ago

Line ET is tangent to circle A and T, and the measure of arc TG is 46 degrees. What is the measure of Angle GET

kogti [31]

Answer:

$m\angle GET=67^o$

Step-by-step explanation:

<u><em>The picture of the question in the attached figure</em></u>

we know that

The measure of the external angle is the semi-difference of the arches it covers.

so

$m\angle GET=\frac{1}{2}[arc\ TN-arc\ TG]$

Remember that the diameter divide the circle into two equal parts

In this problem

TN is a diameter

we have

$arc\ TN=180^o$ ----> because is half the circle (TN is a diameter)

$arc\ TG=46^o$ ---> is given

substitute

$m\angle GET=\frac{1}{2}[180^o-46^o]=67^o$

7 0

3 years ago

Find the surface area of the rectangular prism. 8 yd 4 yd 5 yd Answer: yd? Submit Answer

Rashid [163]

The area of the circle is 18

3 0

3 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

2 years ago