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2 years ago

Please i need this one in 20 mins please

Mathematics

1 answer:

Sidana [21]2 years ago

6 0

Length of the bottom of the triangle = x
another side =10+2(x)
last side=6x
the equation is 6^2x10

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Please help me to solve this

zzz [600]

Answer:

Below in bold.

Step-by-step explanation:

First find the height by use Pythagoras theorem on the right triangle:

h = sqrt (5^2 - 4^2)

= sqrt 9

= 3.

Volume of the prism = area of the triangle * length

= 1/2 * 3 * 4 * 10

= 1/2 * 12 * 10

= 60 cm^3.

Total area = area of 2 triangles + area 0f 3 rectangles

= 2 * 1/2 * 3 * 4 + 3 * 10 + 4 * 10 + 5 * 10

= 12 + 30 + 40 + 50

= 132 cm^2.

3 0

2 years ago

Explain why Rolle's Theorem does not apply to the function even though there exist a and b such that f(a) = f(b). f(x) = cot x/

nydimaria [60]

$cot(x/2)$ is not differentiable over the interval $[ \pi, 7\pi]$

3 0

2 years ago

Order of operations (19-8)×(10-5)+8

Natali [406]

PEMDAS
(9)(5) + 8
45 + 8
53

5 0

3 years ago

Read 2 more answers

How does the graph change between point A and point C?

Darya [45]

Answer:

A. the graph increases, then decreases

Step-by-step: just took the test:)

5 0

3 years ago

Read 2 more answers

In Argentina, a cow on a ranch is expected to need an average of 4200 m2

nika2105 [10]

The cows of Argentina needs an approximate area of 4200 m² for grazing, and there is a total of 4500 cows.

And we are asked to find the total area of their grazing but in hectares. So, we can write:

$1 \: cow = 4200 \: {m}^{2}$

Then, for 4500 cows:

$4500 \: cows = 4200 \: {m}^{2} \times 4500$

$4500 \: cows = 18900000 \: m {}^{2}$

We know that, 1 hectares = 10000 m² = 10⁴ m²

Then let the area of the field be x in hectares:

$1 \: hectare = 10000 \: {m}^{2}$

$x \: hectare = 18900000 \: {m}^{2}$

Then, putting them in proportion, We will get:

$x = \dfrac{18900000}{10000} hectares$

$x = \boxed{ 1890 \: hectares}$

So, the total area in hectares = 1890 hectares.

And we are done !!

#CarryOnLearning

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6 0

3 years ago