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swat32
2 years ago
13

PLEASE HELP ME I DONT KNOW THE ANSWERR

Mathematics
2 answers:
Rom4ik [11]2 years ago
6 0
I can’t see the question bro
LiRa [457]2 years ago
6 0
Let u = x^(1/3)

Then,

u^2 - 6u - 27 = 0

(u-9)(u+3)=0
u = 9, u = -3

Substitute back

X^(1/3) = 9
(X^(1/3))^3 = 9^3
X = 729

And
X^(1/3) = -3
(X^(1/3))^3 = -3^3
X = -27
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20 points! Clear answers and good descriptions!<br> Thanks! :)
balu736 [363]

Answer:

1= b

2= f

Step-by-step explanation:

8 0
2 years ago
Help<br> Me ? I’m marking brainlist
dsp73

Answer: I belive the answer is C

Step-by-step explanation:

7 0
2 years ago
A pile of 42 coins worth $4.90, consisting of nickels and quarters. How many nickels are there?
Ymorist [56]

Answer:14

Step-by-step explanation:

A nickel is 5 cents (20% of dollar)

and a quarter is 25 cents (25% of dollar)

We have given a pile of 42 coins worth of $4.90

Let x be the no nickels and

y be the no of quarter

therefore

x+y=42    -----1

\frac{x}{4}+\frac{y}{20}=4.90 ---2

Solving \left ( 1\right )&\left ( 2\right ) we get

x=14 & y=28

Therefore no of nickels is 14 & no of quarters is 28

6 0
3 years ago
A fair coin is tossed twice what is the probability that it lands obtaining head and tail 1/8 1/16 1/4 1/2
ra1l [238]
Id say 1/2. Its tossed twice and could go either way.

3 0
3 years ago
A sample was taken of the salaries of 20 employees from a large company. The following are the salaries (in thousands of dollars
seropon [69]

Answer:

21,500

Step-by-step explanation:

Given data ( in thousand ) in this year,

28 31 34 35 37 41 42 42 42 47 49 51 52 52 60 61 67 72 75 77,

If each data is increased by $ 3000 in the next year,

So, the data for the next year,

31 34 37 38 40 44 45 45 45 50 52 54 55 55 63 64 70 75 78 80,

Since, the data is already arranged in the ascending order,

The median is 51 which is between 50 and 52,

Thus, the lower half of the Data is, 31 34 37 38 40 44 45 45 45 50,

Having median Q_1=\frac{40+44}{2} = \frac{84}{2} = 42,

Upper half of the data is 52 54 55 55 63 64 70 75 78 80,

Having median Q_3=\frac{63+64}{2}=\frac{127}{2} = 63.5

Hence, the interquartile range = Q_3-Q_1

= 63.5 - 42

= 21.5

That is, the Interquartile range would be 21, 500.

7 0
3 years ago
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