A trough is 14 ft long and its ends have the shape of isosceles triangles that are 5 ft across at the top and have a height of 1
ft. If the trough is being filled with water at a rate of 15 ft3/min, how fast is the water level rising when the water is 4 inches deep?
1 answer:
Step-by-step explanation:
Using similar triangles, the height and width of the water is proportional to the height and width of the trough.
w / h = 5 / 1
w = 5h
The volume of the water is:
V = AL
V = (½ wh) (14)
V = 7wh
Substituting:
V = 7(5h)h
V = 35h²
Take derivative with respect to time:
dV/dt = 70h dh/dt
Given that dV/dt = 15 and h = ⅓:
15 = 70 (⅓) dh/dt
dh/dt = 9/14
dh/dt ≈ 0.643 ft/min
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Spinner diagram isn't attached. A related spinner diagram has been attached below to provide an hypothetical solution to the problem
Answer:
4 / 15
Step-by-step explanation:
For the numbered spinner :
P(landing on 2) = required outcome / Total possible outcomes
Total possible outcomes = (1, 2, 3) = 3
Required outcome = (1) = 1
P(landing on 2) = 1 /3
Lettered spinner :
P(does not land on b)
Total possible outcomes = (A, B, C, D, E)
Required outcome = (a, c, d, e)
P(does not land on b) = 4 / 5
Hence,
P(lands on 2, does not land on b) in this scenario is :
1/3 * 4/5 = 4 / 15
