Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
If;
A = Adjacent
O = Opposite
H = Hypotenuse
Then,
Sin Ф = O/H
Cos Ф = A/H
Therefore,
(Sin Ф)/Cos Ф) = (O/H)/(A/H) = (O/H)*(H/A) = O/A
Now,
tan Ф = O/A ----
Therefore, it is true that
tan Ф = SinФ/CosФ
Each game was $44.99, if she spent a total of 284.97 and we subtract the cost of the console 284.97 - 194.99 = 89.98, since the two games were equally priced we divide 89.98/2 and get $44.98
Answer:
u gotta divide the 7.5% and the other number that is says (can see the question but there)
Answer:
Simplifying
f(r) = 5 + 1.75r
Multiply f * r
fr = 5 + 1.75r
Solving
fr = 5 + 1.75r
Solving for variable 'f'.
Move all terms containing f to the left, all other terms to the right.
Divide each side by 'r'.
f = 5r-1 + 1.75
Simplifying
f = 5r-1 + 1.75
Reorder the terms:
f = 1.75 + 5r-1
Step-by-step explanation:
tada i think
