Question

Can someone please explain with answer?

Answer 1

Using: A^2+b^2=c^2

A&b= (√10)^2=10

10+10=c^2

20=c^2

(take the square root of 20)

c=2√5

Your answer is D

Answer 2

The answer for this question is D, 2$\sqrt{5}$

We can see that this triangle is a right triangle (because of the box on one of it's angles). In a right triangle, we know that, with a and b being the legs, and c being the hypotenuse, that a² + b² = c². In this case, x is the length of the hypotenuse and $\sqrt{10}$ is the value of both legs.

$\sqrt{10}$² = 10, and x² = x², meaning that

10 + 10 = x²

x² = 20

To find what x is equal to, we take the positive square root of 20 (the length of a side can't be negative).

x = $\sqrt{20}$

Now, we can simplify. $\sqrt{20}$ = $\sqrt{2²*5}$ (that's the prime factorization). But, since we see the number 2 two times in this square root, we can factor it out. The simplified form of our answer is:

2$\sqrt{5}$