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RSB [31]
3 years ago
15

A car traveling 75km/h slows down at a constant 0.50m/s^2 just by letting up the gass. a: calculate the distance the car coasts

before it stops, b the time it takes to stop, and the distance it travels during the first and fifth seconds
Physics
1 answer:
RoseWind [281]3 years ago
8 0

Answer:

d = vi * t + ½ * a * t^2, a = -0.5  

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m  

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 =  106.8m

d6 – d5 = 15.3 m  

Explanation:

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Which equation describes the sum of the vectors plotted below?
bearhunter [10]

Equation C describes the sum of the vectors plotted below.

<h3>What is a vector?</h3>

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

The given points from the graph is obtained as;

a = (2,1)

b = (3,-2)

Vector, OA = 2x + y

Vector, AB = x - 3 y

From the triangular lawe of the vector addition;

\rm r=  \vec{OA} +\vec{OB}\\\\\ r= 2x+y+x-3y \\\\ r= 3x-2y

Hence,option C is correct.

To learn more about the vector refer to the link;

brainly.com/question/13322477

#SPJ1

8 0
2 years ago
B. Find the centripetal force needed to keep an 60.0 kg rider traveling in a circle in the ride.
schepotkina [342]

Answer:

loloololo

lol

Explanation:

lolloolololo

8 0
3 years ago
A 300 g glass thermometer initially at 23 ◦C is put into 236 cm3 of hot water at 87 ◦C. Find the final temperature of the thermo
DIA [1.3K]

Answer:

74^{\circ} C

Explanation:

We are given that

Mass of glass,m=300 g

T_1=23^{\circ}

Volume,V=236cm^3

Mass of water=density\times volume=1\times 236=236 g

Density of water=1g/cm^3

Temperature of hot water,T=87^{\circ}

Specific heat of glass,C_g=0.2cal/g^{\circ}C

Specific heat of water,C_w=1 cal/g^{\circ}C

Q_{glass}=m_gC_g(T_f-T_1)=300\times 0.2(T_f-23)

Q_{water}=m_wC_w(T_f-T)=236\times 1(T_f-87)

Q_{glass}+Q_{water}=0

300\times 0.2(T_f-23)+236\times 1(T_f-87)

60T_f-1380+236T_f-20532=0

296T_f=20532+1380=21912

T_f=\frac{21912}{296}=74^{\circ} C

5 0
3 years ago
A 70 ft rope hangs from a helicopter above this room. The rope has a mass per unit length of 2 lb/ft. In order to be rescued fro
Mrac [35]

Answer:

The work done to get you safely away from the test is  2.47 X 10⁴ J.

Explanation:

Given;

length of the rope, L = 70 ft

mass per unit length of the rope, μ = 2 lb/ft

your mass, W = 120 lbs

mass of the 70 ft rope  = 2 lb/ft x 70 ft

                                         = 140 lbs.

Total mass to be pulled to the helicopter, M = 120 lbs  + 140 lbs  

                                                                       = 260 lbs

The work done is calculated from work-energy theorem as follows;

W = Mgh

where;

g is acceleration due gravity = 32.17 ft/s²

h is height the total mass is raised = length of the rope = 70 ft

W = 260 Lb x 32.17 ft/s²  x 70 ft

W = 585494 lb.ft²/s²

1 lb.ft²/s² = 0.0421 J

W = 585494 lb.ft²/s²  = 2.47 X 10⁴ J.

Therefore, the work done to get you safely away from the test is  2.47 X 10⁴ J.

4 0
3 years ago
A person drives a car around a circular cloverleaf with a radius of 77 m at a uniform speed of 10 m/s. What is the acceleration
umka2103 [35]

Answer:

770m/s

Explanation:

caculation using one of the newton law of motion

6 0
3 years ago
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