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QveST [7]
3 years ago
12

A car traveling in a straight line has a velocity of 6m/s at some instant. After 6.32s its velocity is 13.2m/s . What is the ave

rage acceleration in this time interval?
Physics
1 answer:
NeX [460]3 years ago
8 0
Average acceleration  =  (change in speed) / (time for the change) .

Average acceleration  =  (13.2 - 6) / (6.32) = 7.2 / 6.32 = about  <em>1.139... m/s²</em> .
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Find the frequency of light emitted in the transition from the 148th orbit to the 139th orbit. Find the frequency of light absor
Romashka-Z-Leto [24]

Answer:

f=3\times 10^8\times 64.90=19.4\times 10^9 s^{-1}

f=3\times 10^8\times39.9537=119.8613\times 10^8\ /sec

Explanation:

for the transition from 148th orbit to 138th orbit

we know the formula

\frac{1}{\lambda }=R\times \left ( \frac{1}{n^2_{final}}-\frac{1}{n^2_{initial}} \right )

where R is Rydberg constant whose value is  1.0974\times 10^7 /m

putting this value in equation

\frac{1}{\lambda }=1.0974\times 10^7 \left ( \frac{1}{139^2}-\frac{1}{148^2} \right )

\frac{1}{\lambda }=64.9075

f=c\lambda

f=3\times 10^8\times 64.90=19.4\times 10^9 s^{-1}

for the transition from 165th to  174th orbit

we know the formula

\frac{1}{\lambda }=R\times \left ( \frac{1}{n^2_{final}}-\frac{1}{n^2_{initial}} \right )

where R is Rydberg constant whose value is  1.0974\times 10^7 /m

putting this value in equation

\frac{1}{\lambda }=1.0974\times 10^7 \left ( \frac{1}{165^2}-\frac{1}{174^2} \right )

\frac{1}{\lambda }=39.95377

f=c\lambda

f=3\times 10^8\times39.9537=119.8613\times 10^8\ /sec

8 0
3 years ago
What is the fundamental unit for measuring mass in the metric system ?
goldenfox [79]
Kilogram(kg)
It's not the SI unit of mass in the metric system however.
6 0
3 years ago
Read 2 more answers
An air-track glider attached to a spring oscillates between the 10 cm mark and the 60 cm mark on the track. The glider completes
Assoli18 [71]

Answer:

a) Time period is 3.3 seconds

b) The frequency is 0.3030 Hz

c) amplitude is 0.25 m

d) maximum speed is 0.476 m/s

Explanation:

Given the data in the question;

a) Period

Time Period T = Time taken for one oscillation

T = 33s / 10 = 3.3 seconds

Therefore, Time period is 3.3 seconds

b) Frequency

we know that frequency is the inverse of time period

so;

Frequency f = 1/T = 1 / 3.3 s

Frequency f = 0.3030 Hz

Therefore, The frequency is 0.3030 Hz

c) amplitude

amplitude A = \frac{1}{2}( 60 cm - 10 cm )

A = \frac{1}{2} × 50 cm

A = 25 cm

A = 0.25 m

Therefore, amplitude is 0.25 m

d) maximum speed of the glider

maximum speed V_{max} = ωA

and ω = 2π/T

so maximum speed V_{max} = \frac{2\pi }{T}A

so we substitute

so maximum speed V_{max} = \frac{2\pi }{3.3} × 0.25 m

so maximum speed V_{max} = 0.476 m/s

Therefore, maximum speed is 0.476 m/s

5 0
2 years ago
Which process is represented by the PV diagram?
Reika [66]

Hi!


The answer would be A. Isobaric Process


<h3>Explanation:</h3>

Isobaric process is a process where the pressure inside a system remains unchanged. In the Pressure Volume graph given, you can see that the pressure (y axis) remains constant with an increasing volume ( x axis). An example of this would be heating a container with a movable piston. Now, the degree of pressure is dependent on the frequency of collisions of particles inside a system on the walls. If this frequency changes, the pressure changes (proportionally). In our example, heating a container with a movable piston results in the particles inside the container to gain kinetic energy and move faster, meaning an increased frequency of collisions (higher pressure), but at the system time the increase in pressure results in the piston being pushed outwards, causing the volume of the container to increase. This results in decreased frequency of collision of the particles with the walls of the container (lesser pressure). This results in the a zero net effect on the pressure.


Hope this helps!

3 0
3 years ago
Which of these galaxies is most likely to be oldest?
ycow [4]

Answer:

a galaxy observed at a distance of 5 billion light-years

8 0
2 years ago
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