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ohaa [14]
3 years ago
12

Which of the following is a cash transaction?

Mathematics
2 answers:
Ilya [14]3 years ago
6 0
I am pretty sure it is B.) Making change
irina1246 [14]3 years ago
4 0
B.) Making Change

Hope this helps!!
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Evaluate f(x) when x = 3.
klasskru [66]

Answer:

56

Step-by-step explanation:

Since 3 is between -6 and 9 we use the first definition

f(3) = 6 x^2 +2

     = 6(3)^2+2

    = 6(9) +2

   = 54+2

    = 56

3 0
3 years ago
Round 533,786 to nearest hundred thousand
defon

Answer:

500,000

Step-by-step explanation:

it's rounded down to 5 because 3 is less than 5, which means you round down.

4 0
3 years ago
Read 2 more answers
Given that the average rate of change for y = f(x) over the interval [0,3] is −1, the average rate of change over the interval [
Svet_ta [14]

Answer:

Answer is 2

Step-by-step explanation:

We know that average rate of change of a function f(x) in the interval (a,b) is

\frac{1}{b-a} \int\limits^a_b {f(x)} \, dx

Using this we can say that

\int\limits^0_3 {f(x)} \, dx =-1(3)=-3\\\int\limits^2_3 {f(x)} \, dx =5(1)=5\\\\\int\limits^2_6 {f(x)} \, dx =4(5)=20\\

Using properties of integration we have

3 to 6 integral = 20-5 =15

0 to2 integral = -3=5 =-8

Thus integral form 0 to 6 would be = -8+15+5 = 12

Average rate of change form 0 to 6 = \frac{12}{6} =2

Answer is 2

7 0
3 years ago
In your own words, explain to me what is absolute value? Make sure to talk about the definition of it, how you find it, and how
Tom [10]

Answer:

It's a function that associates a real number x with a positive real number using the flowing definition: If the number is not negative (so either positive or 0) the absolute value is x. If x is negative, the absolute value is -x.

This means that to find the absolute value of x you must first determine if x is negative or not, and if it is, multiply it by -1. If it isn't, leave it as it is.

Since the absolute value is a function (of a given number), you can't just plot that number in the number line but the function (so in this case absolute value must be taken first.

The absolute value of x is never negative, so given the absolute value of x we can't determinate if x was positive or negative (if x =/ 0) before the absolute value was taken.

4 0
2 years ago
Solve. (x + 3)^1/2– 1 = x
Natali [406]

Answer:

x=1

Step-by-step explanation:

(x + 3) ^{ \frac{1}{2} }  - 1 = x  \\  \sqrt{x  + 3}   - 1 = x \\  \sqrt{x + 3}  = x + 1 \\ square \: both \: sides \\ x + 3 =  {x}^{2}  + 2x + 1 \\  {x}^{2}  + 2x - x + 1 - 3 = 0  \\  {x}^{2}  + x - 2 = 0  \\ x ^{2}  + 2x - x - 2 = 0  \\ (x^{2}  + 2x) - (x  + 2) = 0 \\ x(x + 2) - 1( x + 2) = 0 \\ (x - 1)(x + 2) = 0 \\ x - 1 = 0 \\ x = 1 \\  \\  \\ x  +  2 = 0 \\ x =  - 2

8 0
3 years ago
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