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Svetlanka [38]
3 years ago
8

Write a number to make the sentence true. 5+4=10_

Mathematics
2 answers:
stira [4]3 years ago
8 0
5+4 = 9
10-1 = 9
The missing number is 1
3241004551 [841]3 years ago
6 0
5+4 = 10 - 1

the missing number is 1
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I need help can someone please help me to understand this
krek1111 [17]
I'm not sure but I think that he had $240 in his savings account. I not sure if the method I used is correct so look at someone else's answer if they have a different amount of money.
5 0
3 years ago
What is angle B?<br><br>A.110<br><br>B.48<br><br>C.55<br><br>D.96
lozanna [386]

Answer:

C

Step-by-step explanation:

Since it gives you the measurement of the are then you can figure out the angle. The arc is 2x as much as the angle.

110/2 = 55

5 0
3 years ago
Which of the following is the closest to 15%? A. 1/7 B. 1/5 c. 1/4 d 1/3
Solnce55 [7]

Answer:

15%=0.15

1÷7=0.14

1÷5=0.2

1÷4=0.25

1÷3=0.33

Step-by-step explanation:

1/7

5 0
3 years ago
Read 2 more answers
A collection of coins consists of nickels, dimes, and quarters. There are three fewer quarters than nickels and six more dimes t
weeeeeb [17]

Answer:

You have 15 dimes. You have 9 quarters. You have 12 nickels

Step-by-step explanation:

lets set some variables:

let "n" = the number of nickels

let "d" = the number of dimes

let "q" = the number of quarters

So, the total amount of money you have should be: $4.35 = 0.25q + 0.10d + 0.05n

Now let's look at the relationships between the coins:

"There are three fewer quarters than nickels": n - 3 = q

"six more dimes than quarters": q + 6 = d

So now you have three equations with three variables, all you need to do is solve.

\left \{ {{4.35 = 0.25q + 0.10d + 0.05n} \atop {n - 3 = q}} \atop {q + 6 = d}}\right.

first, you can substitute "n-3" for "q" (according to the 2nd equation) in the 1st and 3rd equation, you get:

\left \{ {{4.35=0.25(n-3)+0.10d+0.05n} \atop {(n-3)+6=d}} \right.

You now only have two equations and two variables.

Simplify:

\left \{ {{4.35=0.25n-0.75+0.10d+0.05n} \atop {n+3=d}} \right.

\left \{ {{4.35=0.30n-0.75+0.10d} \atop {n+3=d}} \right.

Now substitute "n+3" for "d" (according to the 2nd equation) in the 1st equation:

4.35=0.30n-0.75+0.10(n+3)

simplify:

4.35=0.30n-0.75+0.10n+0.30

4.35=0.40n-0.45

4.35+0.45=0.40n

4.80=0.40n

n=12

You have 12 nickels. Now sub "n" back into your equations to find the number of dimes and quarters:

n - 3 = q

12 - 3 = q

q = 9

You have 9 quarters.

q + 6 = d

9 + 6 = d

d = 15

You have 15 dimes.

3 0
3 years ago
halona walks 1.93 kilometers in 23 minutes, assuming constant speed write a proportion that represents how many kilometers in x
Afina-wow [57]
Dividing 1.93km by 23 minutes, you get 0.083 km per minute, or 5.03 km per hour
4 0
3 years ago
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