Answers:
============================================
Explanation:
Assuming each kick is independent of any other, this means the probability of making two field goals in a row is 0.8*0.8 = 0.64
The probability of missing any single field goal is 1-0.8 = 0.2; so the probability of missing two in a row is 0.2*0.2 = 0.04
----------------
Extra info:
Adding up those results shows that 0.64+0.04 = 0.68 is the probability of either making 2 in a row or missing 2 in a row; that leaves 1-0.68 = 0.32 to represent the probability of making exactly one field goal in either order.
Or you could note that 0.8*0.2+0.2*0.8 = 0.32
If an event occurs 0 times (out of 4, in this case) then it does not occur at least once. So we can find the probability of it not occurring and then subtract that value from 1.
So, what are the chances of it not occurring in 1 trip?
1−.37=.63
What about not occurring in 2 trips?
(1−.37)⋅(1−.37)=.63⋅.63=.3969
Now what about not occurring in 4 trips?
.63^4 = 0.15752961
We must subtract this value from 1
(recall that what we just calculated is the probability of it not occurring, so the probability of it occurring at least once is:
1−0.15752961 = .84247039
TLDR - In 4 trips the chance of a guest catching a cutthroat once in under 4 trips in 0.84.
Answer:
4
Step-by-step explanation:
Answer: πr^2
Step-by-step explanation:
π is pie which is about 3.14
but you need to find the radius and square it is multiply it by itself (Example radius = 2 so 2x2=4)
then multiply the radius squared by π(pie) which is 3.14 or use a calculator.
