let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
Answer:
57.72 in^2
Step-by-step explanation:
Question 1. Shapes are triangle, semi-circle, and rectangle.
Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.
Question 3.
Rectangle's area:<u>48 in^2</u>
Triangles area:8*4/2= <u>16 in^2</u>
Circle Area: pi*r^2/2(since its a semi-circle)
3.14*2^2=3.14*4=12.56/2=<u>6.28 in^2</u>
Question 4.
16-6.28=9.72
9.72+48=57.72 in^2
Answer: i needed this question too!
Answer:
Each angle is 67 degrees
Step-by-step explanation:
Bisected angles are divided in half
134/2 =67
Each angle is 67 degrees
Answer:
140°
Step-by-step explanation:
total angle of a hexagon is 720. We know already 510°. That leaves 210°. The ratio between the two angles is 2:1, therefore angle CDE is 140° and angle DEF is 70 °
