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Paha777 [63]
3 years ago
8

66,681 rounded to the nearest ten thousand??

Mathematics
1 answer:
grandymaker [24]3 years ago
7 0

Hey there! I'm happy to help!

This number is sixty six thousand six hundred eighty one. This means that our ten thousandths place is the first 6.

We look to the right place to see if it is 5 or bigger. It is also six.

Therefore we bump the ten thousands place up 1 to 7 and we make everything else 0, giving us 70,000.

Have a wonderful day! :D

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Paha777 [63]

Answer: 207/4 or -51.75

Step-by-step explanation:

3 0
3 years ago
Probably of Carl solving the 10 problems if there's 20 to study and he knows 15 and ten of the 20 are on the test.
Vladimir79 [104]

Answer:

1/3

Step-by-step explanation:

Probability of solving ten problems by Carl

Given

Total number of problems = 20

Number of problems studied by Carl = 15

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Case I - All ten problems come from the set of known 15 question

10/15 * 10/20 = 1/3

8 0
3 years ago
At the beginning of each of her four years in college, Miranda took out a new Stafford loan. Each loan had a principal of $5,500
kaheart [24]

Answer:

D. $31,337.27

Step-by-step explanation:

We have that the initial amount of the loan is $5500.

Miranda took the loan for 4 years. So, the total present value is $5500×4 = $22,000.

The rate of interest on the loan is 7.5% i.e. 0.075 and it was for the duration of 10 years.

Also, it is given that the loan was compounded annually.

We have the formula as,

P=\frac{\frac{r}{n}\times PV}{1-(1+\frac{r}{n})^{-t\times n}}

i.e. PV=\frac{P\times [1-(1+\frac{r}{n})^{-t\times n}]}{\frac{r}{n}}

Substituting the values, we get,

i.e. PV=\frac{P\times [1-(1+\frac{0.075}{12})^{-10\times 12}]}{\frac{0.075}{12}}

i.e. 22000=\frac{P\times [1-(1+0.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-(1.00625)^{-120}]}{0.00625}

i.e. 22000=\frac{P\times [1-0.4735]}{0.00625}

i.e. 22000=\frac{P\times 0.5265}{0.00625}

i.e. P=\frac{22000\times 0.00625}{0.5265}

i.e. P=\frac{137.5}{0.5265}

i.e. P=261.16

Thus, the total lifetime cost to pay of the loans compounded annually  = 261.16 × 120 = $31,339.2

Hence, the total cost close to the answer is $31,337.27

7 0
3 years ago
Read 2 more answers
A can of tomato soup contains 8 oz of soup the ounces is equal to 28.35 g is how many grams of soup are in the can?
Natalka [10]

Answer:

226.8

Step-by-step explanation:

Multiply 8 x 28.35

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3 years ago
A rule for the nth term of 22,9,-4,-17,-30
fenix001 [56]

Answer: In Exercises 21 and 22, describe and correct the error in writing a rule for the nth term of the arithmetic sequence 22, 9, −4, −17, −30, . . ..

3. 1, −1, −3, −5, −7, . . . 4.

5. 5, 8, 13, 20, 29, . . . 6.

7. 36, 18, 9, —9, —9, . . . 8. 24

9. —1, —3, 1, —5, —3, . . . 10. 24 42

12, 6, 0, −6, −12, . . .

3, 5, 9, 15, 23, . . .

81, 27, 9, 3, 1, . . .

—1 , —1 , —5 , —7 , —3 , . . . 62662

21.

22. ✗

11. WRITING EQUATIONS Write a rule for the arithmetic sequence with the given description.

a. The first term is −3 and each term is 6 less than the previous term.

b. The first term is 7 and each term is 5 more than the previous term.

12. WRITING Compare the terms of an arithmetic sequence when d > 0 to when d < 0.

In Exercises 13–20, write a rule for the nth term of the sequence. Then find a20. (See Example 2.)

The first term is 22 and the common difference is −13.

an =−13+(n−1)(22) an =−35+22n

13. 12, 20, 28, 36, . . . 14. 15. 51, 48, 45, 42, . . . 16.

7, 12, 17, 22, . . .

27. a =−5,d=−—1

17 2 21 2

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29. USING EQUATIONS One term of an arithmetic sequence is a8 = −13. The common difference

is −8. What is a rule for the nth term of the sequence?

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−2, −—4, −—2, —4, . . . 11.7, 10.8, 9.9, 9, . . .

422 Chapter 8 Sequences and Series

✗

Use a1 = 22 and d = −13. a =a +nd

In Exercises 23–28, write a rule for the nth term of th

Step-by-step explanation:

4 0
3 years ago
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