All categories

2 years ago

66,681 rounded to the nearest ten thousand??

Mathematics

1 answer:

grandymaker [24]2 years ago

7 0

Hey there! I'm happy to help!

This number is sixty six thousand six hundred eighty one. This means that our ten thousandths place is the first 6.

We look to the right place to see if it is 5 or bigger. It is also six.

Therefore we bump the ten thousands place up 1 to 7 and we make everything else 0, giving us 70,000.

Have a wonderful day! :D

You might be interested in

I have no clue what it is

Orlov [11]

13.95+2.25+2.25+2.25+2.75+2.75+2.75= 28.95

6 0

2 years ago

PLEASE HELP: CONSUMER MATH

Katen [24]

Answer:

78.09

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can you help me please

Olenka [21]

Answer:

$log_372 = 3.8928$

Step-by-step explanation:

Given

$log_38 = 1.8928$

Required

Evaluate $log_372$

We have:

$log_372 = log_3(8 *9)$

Apply law of logarithm

$log_372 = log_38 +log_39$

Express 9 as 3^2

$log_372 = log_38 +log_33^2$

Evaluate the exponents

$log_372 = log_38 +2log_33$

$log_33 = 1$ .

So:

$log_372 = log_38 + 2 * 1$

$log_372 = log_38 + 2$

Substitute $log_38 = 1.8928$

$log_372 = 1.8928 + 2$

$log_372 = 3.8928$

5 0

2 years ago

Round 8.47285 to 3 decimal places

Elanso [62]

8.473 is the correct answer

7 0

2 years ago

Factor completely 20x^3y + 30x^2y^2.

weqwewe [10]

Answer:

10x^2 y(2x + 3y)

Step-by-step explanation:

20x^3 y + 30x^2 y^2.

Factor 10x^2y out of 20x^3y.

10x^2 y (2x) + 30x^2 y^2

Factor 10x^2y out of 30x^2y^2.

10x^2 y (2x) + 10x^2 y (3y)

Factor 10x^2y out of 10x^2 y (2x) + 10x^2 y (3y).

10x^2 y(2x + 3y)

you factor out 10x^2y from both side which you will then get 10x^2 y (2x) + 10x^2 y (3y) than you factor out 10x^2y again and get 10x^2 y(2x + 3y) your third option

6 0

3 years ago