Answer:
D
Step-by-step explanation:
<span>The diagonals of a parallelogram bisect each other.
So we just equate the two equations BE and DE
2x^2 - x = x^2 + 6
2x^2 - x - x^2 - 6 = 0
x^2 - x - 6 = 0
This is quadratic eqn. So we obtain.
(x - 3) ( x + 2) = 0
Setting each to 0 and solving for x, we have that x = 3 and x = -2
So we have two possible values for BD.
But Since BE = DE then we can simply double each
If x = 3 BD = 2 (2(3)^2 - 3) = 2 ( 18 - 3) = 30 units
If x = - 2 BD = 2((-2)^2 -3 ) = 2 (8 - 3) = 10 units</span>
5x²y²+10x²-7y²-14
Factor 5x² and -7 from the expression to get:
5x²(y²+2)-7(y²+2)
Factor out y²+2 from the equation
(5x²-7)(y²+2)
H< 30
That is your inequality.
Answer:
Step-by-step explanation:
Rationalize the denominator first (keep in mind we are NOT solving this because there is no equals sign here. We are merely simplifying.)
Now simplify by taking the square root of 100 to get:
Divide numerator and denomiator by 10 to get:
