2 years ago

Anybody have a proper answer for this?

Mathematics

1 answer:

skelet666 [1.2K]2 years ago

6 0

John (7%)
Bo (71%)
Mike (75%)

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What is the answer and how do you solve <br><br><br> 21x^3/3x^−1

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Answer:

as written: 7x^2

perhaps intended: 7x^4

Step-by-step explanation:

As written, the Order of Operations specifies that the only denominator factor is 3, so the expression is interpreted as ...

$\dfrac{21x^3}{3}x^{-1}=\dfrac{21}{3}x^{3-1}=7x^2$

___

Sometimes grouping of denominator factors is intended, but parentheses are not written as they should be. If the intention is ...

21x^3/(3x^-1)

then the simplification is ...

$\dfrac{21x^3}{3x^{-1}}=\dfrac{21}{3}x^{3-(-1)}=7x^4$

_____

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

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2 years ago

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The answer is letter B.

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