Answer:
f
(
x
)
=
3
x
3
−
5
x
2
−
47
x
−
15
Explanation:
If the zero is c, the factor is (x-c).
So for zeros of
−
3
,
−
1
3
,
5
, the factors are
(
x
+
3
)
(
x
+
1
3
)
(
x
−
5
)
Let's take a look at the factor
(
x
+
1
3
)
. Using the factor in this form will not result in integer coefficients because
1
3
is not an integer.
Move the
3
in front of the x and leave the
1
in place:
(
3
x
+
1
)
.
When set equal to zero and solved, both
(
x
+
1
3
)
=
0
and
(
3
x
+
1
)
=
0
result in
x
=
−
1
3
.
f
(
x
)
=
(
x
+
3
)
(
3
x
+
1
)
(
x
−
5
)
Multiply the first two factors.
f
(
x
)
=
(
3
x
2
+
10
x
+
3
)
(
x
−
5
)
Multiply/distribute again.
f
(
x
)
=
3
x
3
+
10
x
2
+
3
x
−
15
x
2
−
50
x
−
15
Combine like terms.
f
(
x
)
=
3
x
3
−
5
x
2
−
47
x
−
15
1,000,000/70=approx 142857 mins
142857/60=approx 2381 hours
2381/24=approx 99 days
If you want the answer more precisely then do the same calculations but use the exact value each time
Remember,
To subtract 2/3-1/2 you have to make them equivalent
2/3×2-1/2×3 = 4/6 - 3/6=
1/6
Answer:
7x +5
Step-by-step explanation:
Mason works h hours each day during the 5-day workweek. He also works 5 hours on the weekend. Write an algebraic expression for the number of hours Mason works each week.
"h hours each day in the week"
There are 7 days, so 7 × x.
"5 hours on the weekend"
5
So, this can be written as 7x + 5.
<em>Hope I helped, have a nice day!</em>
<em> -Aadi x</em>
Answer:
$95
Step-by-step explanation:
you had to subtract the two numbers .
