0.10d + 0.25q = 3.55
q = d + 3
0.10d + 0.25(d + 3) = 3.55
0.10d + 0.25d + 0.75 = 3.55
0.10d + 0.25d = 3.55 - 0.75
0.35d = 2.80
d = 2.80/0.35
d = 8.....8 dimes
q = d + 3
q = 8 + 3
q = 11 <=== 11 quarters
Answer:
Step-by-step explanation:
-5x² - 6 = -4x
-5x² + 4x - 6 = 0
a = -5 ; b = 4 ; c = -6
Discriminant = b² - 4ac
= 4² - 4*(-5)*(-6)
= 16 - 120
= -104
roots = 
![=\dfrac{-4+\sqrt{-104}}{2*(-5)};\dfrac{-4-\sqrt{-104}}{2*(-5)}\\\\=\dfrac{-4+2i\sqrt{26}}{-10} ; \dfrac{-4-2i\sqrt{26}}{-10}\\\\=\dfrac{(-2)[2-i\sqrt{26}]}{-10} \ ; \ \dfrac{(-2)[2+i\sqrt{26}]}{-10}\\\\=\dfrac{2-i\sqrt{26}}{5} \ ; \ \dfrac{2+i\sqrt{26}}{5}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B-4%2B%5Csqrt%7B-104%7D%7D%7B2%2A%28-5%29%7D%3B%5Cdfrac%7B-4-%5Csqrt%7B-104%7D%7D%7B2%2A%28-5%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7B-4%2B2i%5Csqrt%7B26%7D%7D%7B-10%7D%20%3B%20%5Cdfrac%7B-4-2i%5Csqrt%7B26%7D%7D%7B-10%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%28-2%29%5B2-i%5Csqrt%7B26%7D%5D%7D%7B-10%7D%20%5C%20%3B%20%5C%20%5Cdfrac%7B%28-2%29%5B2%2Bi%5Csqrt%7B26%7D%5D%7D%7B-10%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2-i%5Csqrt%7B26%7D%7D%7B5%7D%20%5C%20%3B%20%5C%20%5Cdfrac%7B2%2Bi%5Csqrt%7B26%7D%7D%7B5%7D)
Answer:
C & D
Step-by-step explanation:
x² + 3x - 3 = 0
a = co efficient of x² = 1
b= co efficient of x = 3
c = constant = -3
roots = (-b ±
)/2a
= (-3±
)/2*1
= (-3±
)/2
= (-3±√21)/2

The distance between the two points (-1, 4) and (5, 4) is 6 units.
<u>Step-by-step explanation:</u>
The given Coordinate points are (-1, 4) and (5, 4).
The points are considered as (x1,y1) and (x2,y2).
Here,
x1 = -1 and x2 = 5
y1 = 4 and y2 = 4
<u>The distance formula is given by :</u>
Distance = 
<u>To find the distance between these two points :</u>
The distance formula is used,
Distance = 
⇒ √(6)²
⇒ √36
⇒ 6
Therefore, the between the points is 6 units.
Do you need me to simplify ... or what?
Please let me know so I can help you (: