Answer:

Step-by-step explanation:

(x₁, y₁) is the 1st coordinate while (x₂, y₂) is the 2nd coordinate.
Gradient of the line



The value of x in the secants intersection is 1 units
The value of NM in the tangent and secant intersection is 51 units
<h3>How to find length when secant and tangent intersect?</h3>
The first question, two secant intersect outside the circle.
Therefore,
(6x + 8x)8x = (9 + 7)7
14x(8x) = 16(7)
112x² = 112
x² = 112 / 112
x = √1
x = 1
The second question, tangent and secant intersect,
Therefore,
(x + 3)² = (x - 3)(16 + x - 3)
(x + 3)² = (x - 3)(x + 13)
(x + 3)(x + 3) = (x - 3)(x + 13)
x² + 3x + 3x + 9 = x² + 13x - 3x - 39
x² + 9x + 9 = x² + 10x - 39
x² - x² + 9x - 10x = -39 - 9
-x = - 48
x = 48
NM = 48 + 3 = 51 units
learn more on secant and tangent here: brainly.com/question/12477905
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Answer:
Step-by-step explanation:
b) 1- scale factor from the first map to the second map:
= 1.33
2- landmark on the first map is a triangle with side lengths of 3 mm, 4 mm, and 5 mm.
Side lengths of the landmark on the second map
Divide the length by scale factor:
side lengths of 3 mm:
= 2.25 mm
side lengths of 4 mm:
= 3.007 mm
side lengths of 5 mm:
= 3.75 mm