SOLUTION:
PQR is a right-angle triangle.
Therefore, to solve this problem, we will use Pythagoras theorem which is only applicable to right-angle triangles.
Pythagoras theorem is as displayed below:
a^2 + b^2 = c^2
Where c = hypotenuse of right-angle triangle
Where a and b = other two sides of right-angle triangle
Now we will simply substitute the values from the problem into Pythagoras theorem in order to obtain the length of QR.
c = PQ = 16cm
a = PR = 8cm
b = QR = ?
a^2 + b^2 = c^2
( 8 )^2 + b^2 = ( 16 )^2
64 + b^2 = 256
b^2 = 256 - 64
b^2 = 192
b = square root of ( 192 )
b = 13.8564...
b = 13.86 ( to 2 decimal places )
FINAL ANSWER:
Therefore, the length of QR is 13.86 centimetres to 2 decimal places.
Hope this helps! :)
Have a lovely day! <3
Step-by-step explanation:
I am not sure, if something else is missing.
but given that one chart we can say that Craig had 2 fastest throws.
they were in the category 70-75 mph.
but we cannot say precisely which one was faster, and how fast it went.
it is also not clear what is the categorization of a border element (e.g. with an exact speed of 60 mph - is it in the 55-60 or in the 60-65 category ? or both ?).
I assume the upper limit of each interval is included, and the lower limit is excluded.
under this assumption we can say the fastest pitch was faster than 70 mph but slower than or equal to 75 mph.
The answer for this equation is x < 1
