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zimovet [89]
3 years ago
14

A field is to be fertilized at a cost of $0.08 per square yard. the rectangular part of the field is 95 yd long and the diameter

of each semicircle is 49 yd. Find the cost of fertilizing the field.
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
8 0
Assuming that this field is rectangular with 2 semi-circles (one on both ends of the field), we must first calculate the total area of the field. this is done by adding the area of the rectangular portion and the circular portion. This is done below:

Given:

Rectangular length = 95 yards
Rectangular width = semi-circle diameter = 49 yards

Area of rectangle = length * width = 95 * 49
Area of rectangle = 4655 yd^2

The area of the 2 semi-circles can be obtained by treating both as one circle.
Area of circle = pi * (d/2)^2 = 3.1416 * (49/2)^2
Area of circle = 1885.74 yd^2

Total area = 1885.74 + 4655 = 6540.74

We multiply the area by the cost of fertilizing:
Total cost = cost per sq. yd * total area 
Total cost = 0.08 * 6540.74
Total cost = $523.26
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Step-by-step explanation:

Given as :

The office space of building A = 7,500 ft²

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I.e x = \frac{7500}{320}

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Again ,

The office space of building B = 9,500 ft²

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Let The space in building B per square feet per employee = y ft²

So,  y = \dfrac{\textrm office space in building B}{\textrm number of employee in building B}

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∴   y = 29.96 per square feet per employee

<u>So, For building B 29.96 per square feet per employee </u>

So , from calculation it is clear that the square feet of space per employee is more in building B .

Hence The  square feet of space per employee is more in building B .  Answer

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Answer:

Step-by-step explanation:

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Answer:

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