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NemiM [27]
3 years ago
11

60 people attend a game night. Everyone chooses to play chess, a two-player game, or Uno, a

Mathematics
1 answer:
AysviL [449]3 years ago
7 0

Answer:

14-8

12-9

0-15

2-14

Step-by-step explanation:

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I really don't get what I'm supposed to do...​
rusak2 [61]

Answer:

check below

Step-by-step explanation:

1.  c = 68-27 = 41

2. t = 7.9+1.5 =9.4

3. a = 21*3 = 63

4. (multiply whole equation by 8) 8r+6=7, r=1/8

5. x = 25.2/4.2 = 6

6. b = 75/15 = 5

7. A. 6C = 99

B. C = 99/6 = $16.50

The solution represents the cost of one ticket.

5 0
3 years ago
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Plz help ASAP I will add branliest to the first answer, I need to solve for the letter
harkovskaia [24]

Answer:

6. r=2

8.x=3

Step-by-step explanation:

6. 4r-3=5

4r-3=5 add 3 to both sides

4r=8 divide 4 by both sides

r=2

8. 5x-6=9

5x-6=9 add 6 to both sides

5x=15 divide 5 by both sides

x=3

6 0
3 years ago
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En un triangulo ABC, el angulo B mide 64° y el angulo C mide 72°. La bisectriz interior CD corta a la altura BH y a la bisectriz
nadezda [96]

Answer:

The difference between the greatest and the smallest angle of the triangle PBQ is 98°.

Step-by-step explanation:

The question is:

In a triangle ABC, angle B measures 64 ° and angle C measures 72°. The inner bisector CD intersects the height BH and the bisector BM at P and Q respectively. Find the difference between the greatest and the smallest angle of the triangle PBQ.

Solution:

Consider the triangle ABC.

The measure of angle A is:

angle A + angle B + angle C = 180°

angle A = 180° - angle B - angle C

             = 180° - 72° - 64°

             = 44°  

It is provided that CD and BM are bisectors.

That:

angle BCP = angle PCH = 36°

angle CBQ = angle QBD = 32°

angle BHC = 90°

Compute the measure of angle HBC as follows:

angle HBC = 180° - angle BHC + angle BCH

                  = 180° - 90° - 72°

                  = 18°

Compute the measure of angle BPC as follows:

angle BPC = 180° - angle PCB + angle CBP

                  = 180° - 18° - 36°

                  = 126°

Then the measure of angle BPQ will be:

angle BPQ = 180° - angle BPC

                  = 180° - 126°

angle BPQ = 54°

Compute the measure of angle PBQ as follows:

angle PBQ = angle B - angle QBD - angle HBC

                  = 64° - 32° - 18°

angle PBQ = 14°

Compute the measure of angle BQP as follows:

angle BQP = 180° - angle PBQ - angle BPQ

                  = 180° - 14° - 54°  

angle BQP = 112°

So, the greatest and the smallest angle of the triangle PBQ are:

angle BQP = 112°

angle PBQ = 14°

Compute the difference:

<em>d</em> = angle BQP - angle PBQ

  = 112° - 14°

  = 98°

Thus, the difference between the greatest and the smallest angle of the triangle PBQ is 98°.

4 0
3 years ago
X=3y-11, 4x-3y=-26 Substitution
Bad White [126]
=3y-11, 4x-3y=-26 Substitution

3 0
3 years ago
HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
BaLLatris [955]

Answer:

say yolo and go with C

Step-by-step explanation:

6 0
3 years ago
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