Six tenths, one half, two fifths
Answer:
-3r + 15 ---> answer
Step-by-step explanation:
r < 5
You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.
3r < 15
Now, subtract 15 from both sides, you will get this:
3r < 15
-15 -15
-------------
3r — 15 < 0
Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.
So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l
Step-by-step explanation:
We have:
x - y = 43 , xy = 15
To find, the value of x^2+y^2x
2
+y
2
= ?
∴ x - y = 43
Squaring both sides, we get
(x - y)^2(x−y)
2
= 43^243
2
⇒ x^2+y^2x
2
+y
2
- 2xy = 1849
Using the algebraic identity,
(a - b)^2(a−b)
2
= a^2+b^2a
2
+b
2
- 2ab
⇒ x^2+y^2x
2
+y
2
= 1849 + 2xy
Put xy = 15, we get
x^2+y^2x
2
+y
2
= 1849 + 2(15)
⇒ x^2+y^2x
2
+y
2
= 1849 + 30
⇒ x^2+y^2x
2
+y
2
= 1879
∴ x^2+y^2x
2
+y
2
= 1879
I will send hint follow this hint then slove it .
thankyou
You can see how this works by thinking through what's going on.
In the first year the population declines by 3%. So the population at the end of the first year is the starting population (1200) minus the decline: 1200 minus 3% of 1200. 3% of 1200 is the same as .03 * 1200. So the population at the end of the first year is 1200 - .03 * 1200. That can be written as 1200 * (1 - .03), or 1200 * 0.97
What about the second year? The population starts at 1200 * 0.97. It declines by 3% again. But 3% of what??? The decline is based on the population at the beginning of the year, NOT based no the original population. So the decline in the second year is 0.03 * (1200 * 0.97). And just as in the first year, the population at the end of the second year is the population at the beginning of the second year minus the decline in the second year. So that's 1200 * 0.97 - 0.03 * (1200 * 0.97), which is equal to 1200 * 0.97 (1 - 0.03) = 1200 * 0.97 * 0.97 = 1200 * 0.972.
So there's a pattern. If you worked out the third year, you'd see that the population ends up as 1200 * 0.973, and it would keep going like that.
So the population after x years is 1200 * 0.97x
The median of the stem-and-leaf plot is 23
