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3 years ago

Which pair of ratios is proportional? A. 5:7 and 25:35 B. 6:9 and 18:36 C. 9:18 and 16:36 D. 35:120 and 75:250

1 answer:

6 0

One way is to make into fracitons and simplify

A.5/7=25/35?
yes, true

B. 6/9=18/36?
no

C. 9/18=16/36?
no

D. 35/120=75/250?
no

another way is
if a/b=c/d, then (ad)/(bc)=1 or ad=bc

A is answer

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Red car: 25.6/0.80 =32 miles per gallon

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John paid $450 for a new mountain bicycle to sell in his shop. He wants to price it so that he can offer a 10% discount but stil

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Step-by-step explanation:

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Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

Let X = Math scores on the SAT exam

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = 0.38292

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

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