<h3>
Answer:</h3>
A and C
<h3>
Step-by-step explanation:</h3>
Given:
-60x+32 = Qx+P
Find:
Which values of P and Q result in an equation with no solutions? Choose all answers that apply:
(Choice A) A Q=-60 P=60
(Choice B) B Q=32 P=60
(Choice C) C Q=-60 P=−32
(Choice D) D Q=32 P=−60
Solution:
The equation will have no solution if it reduces to ...
0 = (non-zero constant)
If we add 60x-32 to both sides, we get
0 = 60x +Qx + P-32
0 = (Q+60)x +(P-32)
The x-term must be zero, so Q+60 = 0, or Q = -60.
The constant term must be non-zero, so P-32 ≠0, or P ≠ 32.
The appropriate answer choices are those with Q=-60 and P≠32, A and C.
Answer:
y = 2 + 2x
Step-by-step explanation:
6x-3y= -6
-3y = -6 -6x
3y = 6 + 6x
y = 2 + 2x
Answer:
9
Step-by-step explanation:
if the opposition of a number is equal to -9.
hence the expression above....
Answer:
The third option, y=(-1/3)x-7
Step-by-step explanation:
To find a line perpendicular to an equation, you find the negative reciprocal of the slope. For instance, if you have an equation y=4x+5, the negative reciprocal is y=(-1/4)x+5. That is the equation to find a line perpendicular to this.
If you want to find a line parallel to the equation y=4x+5, all you have to do is come up with another equation that has the same slope. So, y=4x+8 would be a line parallel to the equation y=4x+5.
3x+22.5 = 69.75
-22.5 -22.5
3x = 47.25
/3 /3
x = 15.75
The price of each shirt before tax is $15.75
