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natita [175]
3 years ago
14

( ) ÷ (0.6) = -0.7nnnnnnnnnnnnnn​

Mathematics
1 answer:
rodikova [14]3 years ago
8 0

Answer:

there is no answer for this

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What number goes in the box to make the equation true? Blank = 5/16 x 8/15
Sidana [21]

Answer:

The blank box is 1/6

Step-by-step explanation:

5/ 16 x 8/15 = 40/240

40/240 simplified = 1/6

3 0
3 years ago
Read 2 more answers
Find the interest due on $600 at 9.5% for 120 days.
KATRIN_1 [288]

Answer:

Interest= $ 18.73

Step-by-step explanation:

Given : $600 at 9.5% for 120 days

To find : Find the interest due

Solution :

Simple interest formula  I=P\times r\times t

Principle(P)=$600 , rate(r)=9.5%=0.095 , time (t)= 120 days

In years, 1 year = 365 days

1 day = \frac{1}{365} year

120 days = \frac{120}{365} year

Put values in the formula

I=P\times r\times t

I=600\times 0.095\times\frac{120}{365}

 I=\frac{6840}{365}=18.73

Therefore, Interest= $ 18.73




5 0
3 years ago
Read 2 more answers
What is the solution to the systems of equations?<br> y= 2/3x + 3<br> x=-2
Romashka [77]

Answer:

y = 8/3

Step-by-step explanation:

x = -2

y = 2/(3*-2) + 3

y = 2/-6 + 3

y = -1/3 + 3

y = -1/3 + 9/3

y = 8/3

8 0
3 years ago
Henry buys a large boat for the summer, however he cannot pay the full amount of $32,000 at
Anna007 [38]

Answer:

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

Step-by-step explanation:

Loan payment per month=Amount to pay÷discount factor

Mathematically  P=A÷D

where D is the discount factor calculated using the formula;

\frac{(1+i)^n-1}{i(1+i)^n}

where i=periodic interest rate=annual rate divided by number of payment periods

A is the amount to pay after downpayment

P is the loan monthly payment amount

n=number of periodic payments=payments per year times number of years

⇒In this question you find the discount factor then divide the amount remaining to pay with the discount factor to get monthly payments

Given;

Cost of boat=$32000

Down payment=$14000

Loan to pay=$32000-$14000=$18000

Annual rate=5.5%=i=5.5%÷12=0.458%⇒0.00458

Periodic payments, n=4×12=48

Finding the discount factor D;

D=\frac{(1+i)^n-1}{i(1+i)^n} \\\\\\D=\frac{(1+0.00458)^{48} -1}{0.00458(1+0.00458)^{48} } \\\\\\D=\frac{1.2455-1}{0.005703} \\\\\\D=\frac{0.2455}{0.005703} =43.05

To get the amount to pay monthly divide the loan to pay with the discount factor

=\frac{18000}{43.05} =418.14

Monthly payments=$418.14

Total amount will be=down payment + 48×$418.14

$14000+$20070.84=$34070.84

8 0
3 years ago
A unit of electricity costs 13.2 pence. On average, tanya uses 90 units of electricity per week. She pays for her bill in 12 wee
Scrat [10]

Her electricity bill will be of 14256 pence.

<em><u>Explanation</u></em>

On average, Tanya uses 90 units of electricity per week.

So, the <u>total units of electricity in 12 weeks</u> will be: (90*12)=1080 units

One unit of electricity costs 13.2 pence.

Thus, <u>the total cost for 1080 units</u> will be:  (13.2*1080)pence= 14256 pence.

So, her electricity bill will be of 14256 pence.

7 0
3 years ago
Read 2 more answers
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