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Setler79 [48]
3 years ago
14

State the x- and y-intercepts of each equation. Then use the intercepts to graph the equation.

Mathematics
1 answer:
Sidana [21]3 years ago
7 0

Answer:

X=3/4 y= 3

Step-by-step explanation:


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You buy two T-shirts and I say oh you pay the full price of $12 for the first T-shirt and you get the second T-shirt for have th
Komok [63]
Answer: You paid 3/4 of the full price.

Explanation: Total cost of the two shirts = shirt one ($12) + shirt two (half price, so $6) or $18 all together. If you had paid full price for both shirts, it would have cost you $24, or $12 times 2. 24 - 18 = 6, so you saved six dollars. 24 (full price) divided by 6 = 4, so we know that $6 is 1/4 of the full price. Because of this, we know that the amount you spent ($18) was 3/4 of the full price, since 4/4 (total) - 1/4 (amount saved) = 3/4 (amount spent). Another way to solve this is to simply divide 18 by 24.
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3 years ago
The graph of f(x)=4/x^2-2x-3 is shown. For which values of x is f(x) decreasing?
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Answer:

did u ever find out?

Step-by-step explanation:

4 0
3 years ago
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 LOOK BELOW FOR PICTURE The first Pentagon is dilated to form the second pentagon.
Serggg [28]
The answer is B because 4 x 1.25 is 5
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3 years ago
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What is the greatest fraction you can make using the digits 4, 7, and 9?
wel

Answer:

  (7^9)/4 = 40,353,607/4

Step-by-step explanation:

Assuming each digit is used once and exponentiation is allowed, the largest numerator and smallest denominator will result in the largest fraction.

__

If other functions, such as factorial are allowed, then there might need to be a limit on the number of times they are applied. For example,

  (7!)^(9!)/4 has about 1 million digits

something like ...

  ((7!)^(9!))!/4 has many more digits than that

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6 0
3 years ago
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}

=> \frac{3^{-3} \times 5^{1}}{5^{-2}}

=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
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