Find the measure of CD. Round to the nearest tenth. mCD= [?]

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

8 0

Answer:

The arc CD is: 114.64°

Step-by-step explanation:

The given triangle inside the circle, we can get the trigonometric ratio such as

sin x = opposite / hypotenuse

Here:

The opposite side of angle x = 36.7/2

The hypotenuse = 21.8

Thus,

sin x = [36.7/2] / [21.8]

sin x = 18.35 / 21.8

sin x = 0.8417

x = arc sin (0.8417)

x = 57.32°

Thus, the angle formed at the center by CD is:

2 x 57.32 = 114.64°

Therefore, the arc CD is: 114.64°

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Write an expression in simplest form for the perimeter of each figure

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$Perimeter = 5x + 4x + 2.8y + 2x + 2.2y$

We regroup the like terms to obtain,

$Perimeter = 5x + 4x +2x + 2.8y + 2.2y$

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QUESTION 13

The given figure has two pairs of sides that are equal in length and three unequal sides.

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This will give us

$Perimeter = 6b + 5a + 3b + 4 + 3a + 2b + 5a$

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$Perimeter = 6b + 2b+ + 3b + 5a + 5a +3a + 4 +$

This finally simplifies to ,

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$Perimeter = 11b + 13a + 4 +$

QUESTION 14

This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.

We add all the lengths of the sides of the plane figure to get,

$Perimeter =4j + 4j+ 4j+ 4j + 2h + 2h$

This will simplify to give us,

$Perimeter =16j + 4h$