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erik [133]
3 years ago
8

A university has 28,980 students. In a random sample of 180 students, 12 speak three or more languages. Predict the number of st

udents at the university who speak three or more languages. The expected number of students at the university who speak three or more languages is .
Mathematics
1 answer:
anygoal [31]3 years ago
5 0
Word | know | Unknown
Language| 12 | x
Total | 180 | 28980
Use cross multiply:
12(28980) = 180(x)
347760 = 180x
347760/180=1932
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Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
2 years ago
HELP ME PLZ?!!!?!?!?!?!
miss Akunina [59]

It is.................x+y=5

7 0
3 years ago
Please help 20-23 it is 6th grade math and it is due October 16 please I really need help we are doing simplifying expressions a
mel-nik [20]
Hey I'm in 6th too, Simplify means to solve the prob
8 0
3 years ago
I don't want the answer, but I want to know how you got that answer.
anastassius [24]

Answer:

n = 5

Step-by-step explanation:

4n+5n+15=5n+7n\\\\9n+15=12n\\\\9n+15-15=12n-15\\\\-3n=-15\\\\\frac{-3n=-15}{-3}\\\\ \boxed{n=5}

Hope this helps.

8 0
3 years ago
Evaluate the expression 4−(1−4)−2 =
Cloud [144]

Parentheses first. 1-4= -3. 4-3=1. 1-2=-1.

The answer is -1.

3 0
3 years ago
Read 2 more answers
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