The length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Since Kristin wants to wrap a ribbon around the perimeter of a rectangle, the perimeter of a rectangle P = 2(L + W) where L = length of rectangle and W = width of rectangle.
Given that the perimeter of the rectangle, P = 56 inches and the length of the rectangle, L is five less than twice the width of the rectangle, W we have that
L = 2W - 5
Substituting L into P, we have
P = 2(2W - 5 + W)
P = 2(W - 5)
Since P = 56, we have
2(W - 5) = 56
~Dividing both sides by 2, we have
W - 5 = 56/2
W - 5 = 23
Adding 5 to both sides, we have
W = 23 + 5
W = 28 inches
Substituting W into L, we have
L = 2W - 5
L = 2(28) - 5
L = 56 - 5
L = 51 inches
So, the length of the rectangle is 51 inches while the width of the rectangle is 28 inches.
Learn more about perimeter of a rectangle here:
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Answer:
nopee.it is your work try hard or practice in your textbooks or notebooks.
Step-by-step explanation:
The lines are intersected at point (0, -5). So (0, -5) is the solution.
Answer is the third one
(0,-5 )
Answer:
The slope of this line is 7/4 or 1.74 in decimal form.
m = 7/4 OR m = 1.75
Step-by-step explanation:
slope = y^2 - y^1 / x^2 - x^1
Let's pick any two points from the graph: (-1, -3) and (3, 4)
m = y^2 - y^1 / x^2 - x^1
m = 4 - (-3) / 3 - (-1)
m = 4 + 3 / 3 + 1
m = 7/4
m = 1.75
