There are 5 solutions for this system.
x^2 + 4y^2 = 100 ____1
4y - x^2 = -20 ____2
Add both 1 & 2 together. x^2 gets cancelled
4y^2 + 4y = 80 (send 80 to the other side and divide by 4)
Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
Solve for y : y = -5 and y = 4
Using the values of y to find the values of x. From equation 1:
x^2 = 100 - 4y^2 x = /100 - 4y^2 (/ means square root) Replace values of y
y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
y = 4, x = /100 - 4(4)^2 = / 100 - 64 = /36 = -6 or 6
Thus we have 6 solutions y = -5, 4 and x = -6, 0, 6
Answer:
The answer is 2.
Step-by-step explanation:
If I have done my math correctly, and I think I have, 1+1 should equal 2. Hope this helps ;)
Step-by-step explanation:
(-2xy^3)^3
(-2(4)(-1)^3)^3
(-2(4)(-1))^3
(8)^3
512
Answer:
If you simplify it you get d^2-4d
Step-by-step explanation:
Answer:
1
Step-by-step explanation:
Distance between x's (Δx)
0
This field is calculated automatically, you cannot change it's value manually.
Distance between y's (Δy)
1
d = √(Δy2 + Δx2) = √(12 + 02) = √1 = 1
