All categories

3 years ago

(4u + 9) + 9u^2 adding & subtracting polynomials

Mathematics

2 answers:

DIA [1.3K]3 years ago

7 0

Answer:

9u² + 4u + 9

Respond w/ any questions...

vfiekz [6]3 years ago

6 0

Answer:

9u^2 + 4u + 9

Step-by-step explanation:

eliminate parentheses - 4u + 9 + 9u^2

rearrange terms - 9u^2 + 4u + 9

You might be interested in

A storage shed is to be built in the shape of a (closed) box with a square base. It is to have a volume of 150 cubic feet. The c

Alenkinab [10]

Answer:

$C(s) = 6s^2 + \dfrac{1500}{s}\\\text{where s is the side of base.}$

Step-by-step explanation:

We are given the following in the question:

A storage shed is to be built in the shape of a (closed) box with a square base.

Volume = 150 cubic feet

Let s be the edge of square base and h be the height.

Volume of cuboid =

$l\times b\times h$

where l is the length, b is the base and h is the height.

Volume of box =

$s^2h = 150\\\\h = \dfrac{150}{s^2}$

Area of base =

$\text{side}\times \text{side} = s^2$

Cost of concrete for the base = $4

Cost of base($) = $4s^2$

Area of roof =

$\text{side}\times \text{side} = s^2$

Cost of material for the roof = $2

Cost of roof ($) = $2s^2$

Area of 4 walls =

$4\times (sh)\\=4sh$

Cost of material for the side = $2.50

Cost of material of side($) =

$2.50\times 4s(\dfrac{150}{s^2})\\\\=\dfrac{1500}{s}$

Total cost

= Cost of base + Cost of 4 sides + Cost of roof

$C(s) = 4s^2 + \dfrac{1500}{s} + 2s^2\\\\C(s) = 6s^2 + \dfrac{1500}{s}$

is the required cost function.

5 0

3 years ago

A triangular prism container is full of water of 428 cubic cm. The water is 10 cm deep, what is the base area of the container?

Hatshy [7]

<h3>The base area of triangular prism container is 42.8 cubic centimeter</h3>

Solution:

The volume of triangular prism is given as:

$v = base\ area \times height$

Given that,

A triangular prism container is full of water of 428 cubic cm

The water is 10 cm deep

Therefore,

v = 428 cubic cm

h = 10 cm

Substituting the values we get,

$428 = base\ area \times 10\\\\base\ area = \frac{428}{10}\\\\base\ area = 42.8\ cm^2$

Thus the base area of triangular prism container is 42.8 cubic centimeter

3 0

3 years ago

The area of a rectangular wall of a barn is 32 square feet. It’s length is 4 feet longer than the width. Find the length and wid

Gnom [1K]

Answer:

Step-by-step explanation:

Givens

Area = L * w

w = x

l = x + 4

Area = 32

Solution

32 = x(x + 4)

32 = x^2 + 4x

x^2 + 4x - 32

(x + 8)(x - 4)

Only x - 4 is going to make any sense

x - 4 = 0

x = 4

The width is 4

The length is 4 + 4 = 8

4*8 = 32 which is the area.

6 0

3 years ago

at the city museum child admission is $5.10 and adult admission is $9.60. on thursday 132 tickets were sold for a total sale of

Bad White [126]

C + a = 132.....a = 132 - c
5.10c + 9.60a = 898.20

5.10c + 9.60(132 - c) = 898.20
5.10c + 1267.20 - 9.60c = 898.20
5.10c - 9.60c = 898.20 - 1267.20
-4.50c = - 369
c = -369/-4.50
c = 82 <=== child tickets sold

5 0

3 years ago

find the component equation of the plane which is normal to the vector -2i+5j+k and which contains the point (-10;7;5).

maksim [4K]

Given:

A plane is normal to the vector = -2i+5j+k

It contains the point (-10,7,5).

To find:

The component equation of the plane.

Solution:

The equation of plane is

$a(x-x_0)+b(y-y_0)+c(z-z_0)=0$

Where, $(x_0,y_0,z_0)$ is the point on the plane and $\left< a,b,c\right>$ is normal vector.

Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is

$-2(x-(-10))+5(y-7)+1(z-5)=0$

$-2(x+10)+5y-35+z-5=0$

$-2x-20+5y-35+z-5=0$

$-2x+5y+z-60=0$

$-2x+5y+z=60$

Therefore, the equation of the plane is $-2x+5y+z=60$ .

4 0

2 years ago