Answer:
xy+2x+3y+6=xy-5 .............(1)
xy-3x+2y-6=xy.....,.,(2)
2x+3y=-11
-4x+2y=6
first equation multiply by 2
(2)*(2x+3y)=-11
4x+6y=-22
-4x+2y=6
8y=-16 y=(-2),,,,, x=(-2,5)
Answer:
The third answer
Step-by-step explanation:
Rate of change is slope which is 10 for the first one and you can use rise over run to find slope for the graph
Answer:
4x is the greatest common factor of those two.
Step-by-step explanation:
(-16x + 12x)
4x (-4 + 3)
4x is the GCF
Why you may ask is 4x the GCF because when you divide 4x from both you're left with -4 + 3...... you can't take out the negative from the 16 because when you check your work negative 4x times 3 gives you negative 12x which isn't the equation you started with. So positive 4x times 3 give you 12x.
Hopes this helps!!!
Answer:
So is there are 10 cats for every 4 dogs,
If there are 5 cats that is half of 10 so half of 4 is 2
Now there are 32 dogs that is 8 times more than 4 so 10 x 4 is 40 so the answers are
Cats 10 5 8
Dogs 4 2 32
Plz give brainiest
This seems to be referring to a particular construction of the perpendicular bisector of a segment which is not shown. Typically we set our compass needle on one endpoint of the segment and compass pencil on the other and draw the circle, and then swap endpoints and draw the other circle, then the line through the intersections of the circles is the perpendicular bisector.
There aren't any parallel lines involved in the above described construction, so I'll skip the first one.
2. Why do the circles have to be congruent ...
The perpendicular bisector is the set of points equidistant from the two endpoints of the segment. Constructing two circles of the same radius, centered on each endpoint, guarantees that the places they meet will be the same distance from both endpoints. If the radii were different the meets wouldn't be equidistant from the endpoints so wouldn't be on the perpendicular bisector.
3. ... circles of different sizes ...
[We just answered that. Let's do it again.]
Let's say we have a circle centered on each endpoint with different radii. Any point where the two circles meet will then be a different distance from one endpoint of the segment than from the other. Since the perpendicular bisector is the points that are the same distance from each endpoint, the intersection of circles with different radii isn't on it.
4. ... construct the perpendicular bisector ... a different way?
Maybe what I first described is different; there are no parallel lines.
