Answer:
the Velocity of the plane is 100 mi/hr along the northeast direction
Step-by-step explanation:
According to the Question,
- Given That, the Initial velocity of the plane is 150 mi/hr along the east north direction and the wind is blowing at 50 mi/hr along the southwest direction
since the velocity of wind and plane is exactly opposite
- the relative velocity of the plane with respect to the wind is given by
, where
is the velocity of plane = 150mi/hr and
= velocity of wind = 50 mi/hr
- Therefore, Relative Velocity = 150-50 ⇒ 100mi/hr along northeast direction
Thus, the velocity of the plane is 100 mi/hr along the northeast direction
3x^2 + 5xy - 2y^2
Simplifying:
3x^2 + 5xy + - 2y^2
Reorder Terms:
5xy +3x^2 + - 2y^2
Factor a Trinomial.
(3x + - 1y)(x + 2y)
Final Result:
(3x + - 1y)(x + 2y)
Hope this helps!!!
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