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3 years ago

7

What is the value of (-5)^4?

2 answers:

AfilCa [17]3 years ago

7 0

—625 because you would multiply -5 four times

Ksenya-84 [330]3 years ago

3 0

Answer:

625

Step-by-step explanation:

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2 4/5 divided by 2/3

daser333 [38]

Answer:

4.2 cuz yeah

Yeet :)

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3 years ago

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What is the trigonometric ratio for cosn? enter your answer, as a simplified fraction, in the boxes. $$ triangle l m n with righ

hjlf

The trigonometric ratio will be Cos(n)=12/13

<h3>What will be the trigonometry ratio?</h3>

Given is a Right triangle LMN with right angle at M i.e. angle M = 90 degrees.

Given are the sides LM = 15, MN = 36, and LN = 39.

It says to find cos(n) = ?

So opposite side would be LM, adjacent side would be MN, and LN is the hypotenuse.

We know that the cosine ratio is given by :-

$Cos(n)=\dfrac{adjacent}{Hypotenuse}$

$Cos(n)=\dfrac{MN}{LN}$

$Cos(n)=\dfrac{36}{39}$

$Cos(n)=\dfrac{12}{13}$

Hence the required ratio will be $Cos(n)=\dfrac{12}{13}$

To know more about trigonometry, follow

trigonometry

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2 years ago

What is 19.2 * 10^8 minutes in hours? Written in scientific notation form?

Lena [83]

Answer should be 1.85 x 10^18

7 0

3 years ago

The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde

Akimi4 [234]

we are given

quadratic equation as

$3x^2-4x+15=0$

now, we can find b and c from

$x^2+bx+c=0$

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

$3x^2-4x+15=0$

$\frac{3x^2-4x+15}{3}= \frac{0}{3}$

$\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}$

now, we can simplify it

$x^2-\frac{4}{3}x+5= 0$

now, we can compare it with

$x^2+bx+c=0$

we get

$b=-\frac{4}{3}$

$c=5$

so, we get order pair as

$(b,c)=(-\frac{4}{3} , 5)$ ..............Answer

6 0

3 years ago

Read 2 more answers

Use substitution to solve the following system of linear equations and fill in the following blanks:

marissa [1.9K]

Answer:

$x=-4$

$y=3$

$z=-5$

Step-by-step explanation:

<u>Given:</u>

$x+y+z=-6$

$x-6y-7z=-29$

$-7y-5z=4$

<u>Solve for </u> $x$ <u> in the 1st equation:</u>

$x+y+z=-6$

$x+y=-z-6$

$x=-y-z-6$

<u>Substitute the value of </u> $x$ <u> into the 2nd equation and solve for </u> $z$ <u>:</u>

$x-6y-7z=-29$

$(-y-z-6)-6y-7=-29$

$-7y-z-13=-29$

$-7y-z=-16$

$-z=-16+7y$

$z=16-7y$

<u>Substitute the value of </u> $z$ <u> into the 3rd equation and solve for </u> $y$ <u>:</u>

$-7y-5z=4$

$-7y-5(16-7y)=4$

$-7y-80+35y=4$

$28y-80=4$

$28y=84$

$y=3$

<u>Plug </u> $y=3$ <u> into the solved expression for </u> $z$ <u> and evaluate to solve for </u> $z$ <u>:</u>

$z=16-7(3)$

$z=16-21$

$z=-5$

<u>Plug </u> $z=-5$ <u> into the solved expression for </u> $x$ <u> and evaluate to solve for </u> $x$ <u>:</u>

$x=-(3)-(-5)-6$

$x=-3+5-6$

$x=2-6$

$x=-4$

Therefore:

$x=-4$

$y=3$

$z=-5$

6 0

3 years ago