Please help me with this question!!

Cody was 165 cm tall on the first day of school this year, which was 10% taller than he was on the first day of school last year

zhenek [66]

Solution:

Let X = height of Cody on the first day of school last year

Given: Y= height of Cody on the first day of school year = 165 cm

10%(X)+X=Y

.10(X)+X=165

1.10X=165

X=165/1.1

X= 150 cm = height of Cody on the first day of school last year

3 0

3 years ago

-Brainliest please help ignore the selected option in q1

labwork [276]

Answer:

D. 17,15,13,11

Step-by-step explanation:

The expression states that the next term in this sequence is formed by subtracting 2 from the preceding (n-1) result. We know that for n = 1 that f(1) = 17.

f(n) is f(n-1) - 2

so

f(2) = f(1) - 2

f(2) = 17 - 2 or 15

f(3) = f(2) - 2

f(3) = 15 - 2 or 13

f(4) = f(3) - 2

f(4) = 13 - 2 or 11

. . . .

and so on.

4 0

2 years ago

Read 2 more answers

An elevator has a placard stating that the maximum capacity is 1580 lb-10 passengers. So, 10 adult male passengers can have a m

disa [49]

Answer:

a) 0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb

b) No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 160 lb and a standard deviation of 35 lb.

This means that $\mu = 160, \sigma = 35$

Sample of 10:

This means that $n = 10, s = \frac{35}{\sqrt{10}} = 11.07$

a) Find the probability that it is overloaded because they have a mean weight greater than 158 lb.

This is 1 subtracted by the pvalue of Z when X = 158. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{158 - 160}{11.07}$

$Z = -0.18$

$Z = -0.18$ has a pvalue of 0.4286

1 - 0.4286 = 0.5714

0.5714 = 57.14% probability that it is overloaded because they have a mean weight greater than 158 lb.

b.) Does this elevator appear to be safe?

No, because the probability of being overloaded is considerably high(57.14%). Ideally, it should be under 5%, which would be considered an unusual event.

8 0

3 years ago

Use the diagram of the right triangle above and round your answer to the nearest hundredth. If m a. 17.32 m b. 6.93 m<b

zepelin [54]

In ΔABC,
tanA = a/b
∴ a = b×tanA = 12×1/√3 = 6.928 ~ 6.93 m

7 0

3 years ago

The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain? A. {5, 8} B. {-5, -8} C. {3, 8} D. {4,

Sergeu [11.5K]

Answer:

Option D

The domain of the function is: {4, 7}

Step-by-step explanation:

We know that for polynomial functions like $f(k) = k^2 + 2k + 1$ its domain and its rank are all real numbers. However, for this case we are told that the function range is: the set {25, 64}