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Irina-Kira [14]
3 years ago
5

دریافت رمزدوم کارت عابربانک ملت بهاره تبری

Mathematics
1 answer:
dolphi86 [110]3 years ago
8 0
<span>Receive a reminder of the bank card for the people of the spring of Tabari?

</span>
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Find the area of the region in two ways. a. Using integration with respect to x. b. Using geometry. 9-x
Natali [406]

Answer: hello your question is incomplete attached below is the complete question

answer :

a)   \int\limits^3_0 {(10-x)-(x+4)} \, dx     ( option D )

b) A =  1/2 (6)(3)   ( option B )

c) Area of shaded region = 9

Step-by-step explanation:

<u>a) Using integration with respect to x </u>

Area =   \int\limits^7_4 {(y-4)} \, dy + \int\limits^a_7 {(10-y)} \, dy         ( note a = 10 )

          = y^2/2 - 4y |⁷₄  + 10y - y^2/2 |¹⁰₇

          = 33/2 - 12 + 30 - 51/2   = 9

hence the best integral from the options attached is option D

\int\limits^3_0 {(10-x)-(x+4)} \, dx

= [ 10x - x^2 /2 - x^2/2 - 9x ] ³₀

= 30 - 9/2 - 9/2 - 12  = 9

<u>b) Using Geometry </u>

Area = 1/2 * base * height

        = 1/2 * 6 * 3

        = 9

7 0
3 years ago
Please help. Find the value of x in the triangle shown below.<br> 5<br> 8
Levart [38]

Answer:

x=+-\sqrt{89}

Step-by-step explanation:

x^{2}=8^{2} + 5^{2}

x^{2}=64+25

x^{2}=89  

x=+-\sqrt{89}

4 0
3 years ago
Hurry and help and and give me the correct answer and you will get The brain thing
Evgesh-ka [11]

x = 130 is your answer

130 - 20 = 110

Since line E and F are parallel and are straight lines, we know both angles will add up to 180°

110 + 70 = 180

7 0
3 years ago
-3x=4(3x-2)+1<br> What is the solution for x?
romanna [79]
Use a app called photo math it works good.
8 0
3 years ago
Read 2 more answers
Unoccupied seats on flights cause airlines to lose revenue. Suppose a large airline wants to estimate its average number of unoc
Bingel [31]

Answer:

We need a sample size of at least 719

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?

This is at least n, in which n is found when M = 0.3, \sigma = 4.103. So

M = z*\frac{\sigma}{\sqrt{n}}

0.3 = 1.96*\frac{4.103}{\sqrt{n}}

0.3\sqrt{n} = 1.96*4.103

\sqrt{n} = \frac{1.96*4.103}{0.3}

(\sqrt{n})^{2} = (\frac{1.96*4.103}{0.3})^{2}

n = 718.57

Rouding up

We need a sample size of at least 719

6 0
3 years ago
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