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Xelga [282]
3 years ago
11

Please help me ill give you the crown thing if its right

Mathematics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer: The new price is $840

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Graph the function by making a table of values which table is correct
Talja [164]

It is often more convenient to evaluate a polynomial when it is written is "Horner form."

... f(x) = (((10x -4)x -8)x +3)x -6

The graphs offered can be distinguished by their values of f(1) and f(2), so our table can be a short one.

... f(1) = (((10·1 -4)1 -8)1 +3)1 -6 = -5 . . . . . . . eliminates graph d

... f(2) = (((10·2 -4)2 -8)2 +3)2 -6 = 96 . . . . eliminates graphs a and c

The appropriate choice is b.

3 0
3 years ago
Pleasee help ASAP!! No links pleaseee!!!
Ilya [14]

Given:

The vertices of the rectangle ABCD are A(0,1), B(2,4), C(6,0), D(4,-3).

To find:

The area of the rectangle.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using the distance formula, we get

AB=\sqrt{(2-0)^2+(4-1)^2}

AB=\sqrt{(2)^2+(3)^2}

AB=\sqrt{4+9}

AB=\sqrt{13}

Similarly,

BC=\sqrt{(6-2)^2+(0-4)^2}

BC=\sqrt{(4)^2+(-4)^2}

BC=\sqrt{16+16}

BC=\sqrt{32}

BC=4\sqrt{2}

Now, the length of the rectangle is AB=\sqrt{13} and the width of the rectangle is BC=4\sqrt{2}. So, the area of the rectangle is:

A=length \times width

A=\sqrt{13}\times 4\sqrt{2}

A=4\sqrt{26}

A\approx 20

Therefore, the area of the rectangle is 20 square units.

3 0
3 years ago
The endpoints of GH are G(10,1) and H(3,5). What is the midpoint of GH?
svet-max [94.6K]

Answer:

The answer is (6.5,3)

Step-by-step explanation:

The solution is in the image

8 0
2 years ago
Comparing Absolute Values
AURORKA [14]

Answer:

i don not know this. but I think

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Dan takes an airplane to visit his parents. He pays the airline a total of $450. The cost of the ticket is $315. The airline als
vredina [299]

Answer:

9

Step-by-step explanation:

Start with the total amount Dan paid and subtract the part of the payment that is for the ticket.

450-315=135

Assuming that all of that $135 was for luggage fees and each pound over the limit costs $15, then the question is, how many times did Dan pay $15 until he'd paid the full $135 luggage fee.

So divide $135 by $15.

135/15=9

So his luggage weighted 59 pounds, which is 9 pounds over the limit.

6 0
2 years ago
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