Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Answer:
4/5
Step-by-step explanation:
Common factor is 3 so,
if you divide 12/15 by 3, then it will equal to 4/5
Let me try all my best for this
Please , open the file
The answer is b. angles p and s; angles q and r
Answer:
x = -1 and y = 1/2
Step-by-step explanation:
Let u = 1/x, and v = 1/y
Then the pair of equations
-3/x + 4/y = 11
1/x - 2/y = -5
Can be written as
-3u + 4v = 11 .................................(1)
u - 2v = -5......................................(2)
From (2)
u = 2v - 5 .......................................(3)
Substituting (3) into (1)
-3(2v - 5) + 4v = 11
-6v + 15 + 4v = 11
-6v + 4v = 11 - 15
-2v = -4
v = 4/2 = 2
Substituting this value of v in (3)
u = 2v - 5
u = 2(2) - 5
= 4 - 5
= -1
That is
u = -1, v = 2
Since u = 1/x, and v = 1/y, we have
1/x = -1
=> x = -1
And
1/y = 2
=> y = 1/2
Therefore
x = -1 and y = 1/2
