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Irina18 [472]
2 years ago
11

Somebody help me out ols

Mathematics
1 answer:
enot [183]2 years ago
3 0

Answer:

Can I afford this, How will I pay for it, and what are the consequences of my purchase.

Step-by-step explanation:

Best questions to stay out of debt.

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Please classify the real number: 9.63 with 63 being repeated
prisoha [69]

Answer:

Step-by-step explanation:

9.63636363636363636363636363

7 0
3 years ago
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Second grade Solve using algorithm. Draw chips and bundle when you can
Anastasy [175]
Idk what your answer will be i had it then i lost it sorry
4 0
3 years ago
i have 30 coins, all nickels, dimes and quarters, worth $4.60. there are two more dimes than quarters.. how many of each kind of
Oliga [24]

Answer:

Step-by-step explanation:

I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.

..

let quarters be x

dimes = x+2

...

dimes + quarters = x+x+2=2x+2

...

nickels = 30-(2x+2)

...

5(30-(2x+2))+10(x+2)+25x=460

5(30-2x-2)+10x+20+25x=460

150-10x-10+10x+20+25x=460

160+25x=460

-160

25x=460-160

25x=300

/25

x=300/25

x=12 ---- quarters

x+2= 12+2=14 dimes

30-(2x+2)=4 nickels

...

check

4*5+14*10+12*25=20+140+300=460

4 0
2 years ago
The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of 20. Each d
liberstina [14]

Answer: 0.0516

Step-by-step explanation:

Given : The number of defective components produced by a certain process in one day has a Poisson distribution with a mean of \lambda=20.

The probability mass function for Poisson distribution:-P(X=x)=\dfrac{e^{-\lambda}\lambda^x}{x!}

For x= 15 and  \lambda=20 , we have

P(X=x)=\dfrac{e^{-20}(20)^{15}}{15!}=0.0516488535318\approx0.0516

Hence, the probability that exactly 15 defective components are produced in a particular day = 0.0516

7 0
3 years ago
10x0+10x1<br> what is the answer ?
sesenic [268]

Answer:

10

Step-by-step explanation:

10x0 is 0

10x1 is 10

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